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Rufina [12.5K]
3 years ago
14

Which of the following is a vector quantity?

Physics
2 answers:
mestny [16]3 years ago
5 0
A is the answer  of course
olga55 [171]3 years ago
5 0

D. 55mph to the south

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What is the speed of an electron traveling 32 cm in 2 ns?
abruzzese [7]

Answer:

Speed, v=1.6\times 10^8\ m/s

Explanation:

Given that,

Distance covered by the electron, d = 32 cm = 0.32 m

Time, t = 2 ns

We need to find the speed of an electron. Speed is equal to distance covered divided by time. So,

v=\dfrac{0.32}{2\times 10^{-9}}\\\\v=1.6\times 10^8\ m/s

So, the speed of the electron is 1.6\times 10^8\ m/s.

6 0
3 years ago
The velocity of a ball as it is thrown up is 20 meters/second. It attains zero velocity after 3.5 seconds. What is the average a
ArbitrLikvidat [17]
Acceleration = (final velocity - initial velocity) / time
Acceleration = 20 - 0 / 3.5
= 5.714 m/s^2

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8 0
4 years ago
Read 2 more answers
ASAP pls answer right and I will mark brainiest
Ronch [10]
1. D:Asteroids have geological activity
2.A:Short-period comets circle around the sun in 200 years or less and originate in the Kuiper Belt
3.D:All of the above
4.A:It’s gravity is too weak to clear it’s orbit
5.B:Ceres
6.C:Haumea
7.A:Is bigger than Pluto

I hope this helps
6 0
3 years ago
What's the definition of wavelength?
mario62 [17]
The Wavelength is the distance between the same points on two adjacent (neighbouring) disturbances (e.g. from crest to crest or from compression to compression) i.e. one full cycle of the wave.
4 0
3 years ago
An amplifier produces a sound wave with a power of 1.00 μW (micro-Watt). If it is a point source and radiates uniformly in all d
gtnhenbr [62]

Answer:

(a) I=8.84*10^{-9}W/m^{2}

(b) \beta =39.46dB

Explanation:

Given data

The source is 1.00 μW

The point is 3m away from the point source

For Part (a)

The intensity at a certain distance from a point source that emits sound wave is given as:

I=\frac{P_{s} }{4\pi r^{2} }\\I=\frac{1*10^{-6}W  }{4\pi (3m)^{2} } \\I=8.84*10^{-9}W/m^{2}

For Part (b)

The Sound level is given by

β=(10dB)×log(I/I₀)

Where

I₀=1×10⁻¹²W/m²

Substitute the given values to find Sound level

So

\beta =(10dB)log(\frac{8.84*10^{-9}W/m^{2}  }{1*10^{-12}W/m^{2}} )\\\beta =39.46dB

4 0
3 years ago
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