Is number 4 correct?

Which best explains whether a triangle with side lengths 5 cm, 13 cm, and 12 cm is a right triangle? The triangle is a right tri

stira [4]

Answer:

The Triangle Is A Right Triangle Because 5^2 + 12^2 = 13^2.

Step-by-step explanation:

5^2 = 25. 12^2 = 144. With the Pythagorean theorem, (a^2 + b^2 = c^2), 5 is a, 12 is b, and 13 is c.

25 + 144 = 169.

13 ^ 2 = 169.

Since a^2 + b^2 = c^2 is true, the triangle is a right triangle.

3 0

3 years ago

Read 2 more answers

3.<br> Find the value of X 11x-2 19x+3 9x+1 PLEASE LOOK AT PICTURE

Mila [183]

Answer:

x=4

Step-by-step explanation:

1) first write it down --> 11x-2+9x+1=19x+3

2) then combine like terms on the left side of the equation. --> 20x-1=19x+3

3) Then subract 19x on both sides --> x-1=3

4) After add 1 to both sides --> x=4

5 0

4 years ago

Can someone help with this problem? ASAP

Leona [35]

I think it May be b because it’s slope is rising by two

4 0

3 years ago

HELP PLEASE ANYONE STEP BY STEP TIMED

UNO [17]

Answer:

$\huge\boxed{\text{B) 4}}$

Step-by-step explanation:

We can use the properties of some of these circles to solve and find the value of x.

FIrst off - we know that to find the side of a right triangle we can use the Pythagorean Theorem, which states that $a^2 + b^2 = c^2$ (a and b being legs, c being the hypotenuse.)

<h2><u>Finding the hypotenuse</u></h2>

We also know that this triangle is in a circle. Part of the hypotenuse and the altitude of the triangle are in the circle.

Point W is the center of the circle. Therefore, any points stretching to the edge from it will be equal (since this is a circle).

With this knowledge - UW and WZ are equal.

Therefore, since UW is $x-1$ , WZ will be too.

We also know the length of VZ. We can add this to WZ to find the length of the whole hypotenuse.

$\displaystyle x-1+2 \\ x+1$

So the length of the hypotenuse, WV, is $x+1$ .

<h2><u>Finding the value of x</u></h2>

Now that we know the length of the hypotenuse, we can use the Pythagorean Theorem like we stated before to find the value of x.

We know the two legs are $x-1$ and $2x-4$ , while the hypotenuse is

$\displaystyle (x-1)^2 + (2x-4)^2 = (x+1)^2$
$(x^2 - 2x + 1) + (4x^2-16x+16) = (x^2 + 2x + 1)$ (use FOIL to find the value of each expression squared)
$5x^2 - 18x + 17 = x^2 + 2x + 1$ (simplify the left side)
$4x^2 -20x + 16 = 0$ (subtract both sides by $x^2 +2x + 1$ )
$x = \frac{{ -b \pm \sqrt {b^2 - 4ac} }}{{2a}}$ (Quadratic formula)
$\frac{{ -(-20) \pm \sqrt {(-20)^2 - 4 \cdot 4 \cdot 16} }}{{2 \cdot 4}}$ (plug in values from equation)
$\frac{{ 20 \pm \sqrt {400 - 256} }}{8}}$ (simplify)
$\frac{{ 20 \pm \sqrt {144} }}{8}}$ (simplify)
$\frac{{ 20 \pm 12 }}{8}}$ (simplify)
$\displaystyle x = \frac{20+12}{8} \ \text{and} \ \frac{20-12}{8}$ (use plus/minus to find two roots)
$\displaystyle x = \frac{32}{8} \ \text{and} \ \frac{8}{8}$ (simplify)
$\displaystyle x = 4 \ \text{and} \ 1$