Answer:
the volume of a set of keys is 6.75ml
Answer:
ΔS° = 180.5 J/mol.K
Explanation:
Let's consider the following reaction.
4 NH₃(g) + 5 O₂(g) → 4 NO(g) + 6 H₂O(g)
The standard molar entropy of the reaction (ΔS°) can be calculated using the following expression.
ΔS° = ∑np × S°p - ∑nr × S°r
where,
ni are the moles of reactants and products
S°i are the standard molar entropies of reactants and products
ΔS° = 4 mol × S°(NO(g)) + 6 × S°(H₂O(g)) - 4 mol × S°(NH₃(g)) - 5 mol × S°(O₂(g))
ΔS° = 4 mol × 210.8 J/K.mol + 6 × 188.8 j/K.mol - 4 mol × 192.5 J/K.mol - 5 mol × 205.1 J/K.mol
ΔS° = 180.5 J/K
This is the change in the entropy per mole of reaction.
Answer:
im not sure but i belive its agree
Explanation:
Answer:
185.92 L
Explanation:
Given data:
1 mole = 6.022× 10²³ molecules
1 mole = 22.4 L
Volume occupy by 5.0× 10²⁴ molecules
Solution:
1 mole = 6.022× 10²³ molecules
5.0× 10²⁴ molecules × 1 mole / 6.022× 10²³ molecules
0.83× 10¹ mol
8.3 moles
1 mole occupy 22.4 L
8.3 mol × 22.4 L / 1 mol
185.92 L