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qaws [65]
3 years ago
13

Helpppppp please please

Chemistry
1 answer:
polet [3.4K]3 years ago
6 0
What do we do? hehehehe
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PLEASE HELP!!!<br> ILL MARK AS BRAINIEST AND GIVE YOU 30 POINTS!!!
sweet [91]

Answer:

did u get it yet

Explanation:

6 0
3 years ago
Convert 15.4 moles of Ca3(PO4)2 to grams.
arlik [135]

Answer:

La cantidad de Ca3 (P04) 2 equivalente a 15, 4 moles es de 4774 gramos.

Explanation:

We need the weights of the elementos Ca, P and O, for calculate the weight of 1 mol:

Weight Ca=40 g

Weight P=31 g

Weight 0 = 16 g

Weight Ca3(PO4)2 = 3 x 40 g + 2 x (31 g + 4 x 16 g)

Weight Ca3(PO4)2 =310 g

1 molCa3(PO4)2---- 310 g

15, 4 mol Ca3(PO4)2-----x=(15, 4 molx 310 g)/1 mol = 4774 g

5 0
3 years ago
If this energy were used to vaporize water at 100.0 ∘C, how much water (in liters) could be vaporized? (Assume the density of wa
11Alexandr11 [23.1K]

Answer:

0.425 L  

Explanation:

Given the information from the question.  We know that the water heat evaporation is given by 2261 KJ/kg. Therefore, for each Kg of vapor, 2261 is required.

To calculate the amount of water evaporated by 960 KJ is as follows  

= (1/2260)*960 =0.425 Kg

In other words, 0.425 of water is evaporated by 960 KJ.  

To calculate the volume of water, we have mass and density. Therefore, Volume = Mass/Density = 425g/1g/ml = 0.425 L.

Therefore, water evaporated is 0.425 L  

5 0
4 years ago
A home solar energy unit stores energy for later use. On a sunny day, the temperature of the water in the tank increased from 23
igomit [66]

Answer:

391.46 L

Explanation:

Given:

Initial temperature of the water = 23.4°C

Final temperature of the water = 39°C

Temperature change for the water, ΔT = (39 - 23.4) = 15.6°C

Heat absorbed by the water = 2.55 × 10⁴ kJ = 2.55 × 10⁷ J

Density of the water = 0.998 g/mL

Specific heat of the water, C = 4.184 J/g°C

Now,

The heat absorbed by the water, q = mCΔT

where, m is the mass of the water

Thus,

we have

2.55 × 10⁷ J = m × 4.184 × 15.6

or

m = 390682.45 grams

also,

Density = mass / volume

thus,

0.998 = 390682.45 / volume

or

Volume = 391465.38 mL

or

Volume = 391.46 L

7 0
4 years ago
Which of the quantum numbers relate(s) to the electron only? Which relate(s) to the orbital?
olganol [36]

Answer:

Schrodinger's proposal, considered as the 5th atomic model, is to describe the characteristics of all the electrons in an atom, and for this I use what we know as quantum numbers.

Quantum numbers are called with the letters n, m, l and s and indicate the position and energy of the electron. No electron of the same atom can have the same quantum numbers.

Explanation:

n = main quantum number, which indicates the level of energy where the electron is, assumes positive integer values, from 1 to 7 and it is related to the orbital too.

I = secondary quantum number, which indicates the orbital in which the electron is located, can be s, p, d and f (0, 1, 2 and 3).

m = magnetic quantum number, represents the orientation of the orbitals in space, or the type of orbital, within a specific orbital. Assumes values ​​of the negative secondary quantum number (-l) through zero, to the positive quantum number (+ l).

s = quantum number of spin, which describes the orientation of the electron spin. This number takes into account the rotation of the electron around its own axis as it moves around the nucleus. Assumes only two values ​​+1/2 and - 1/2

5 0
3 years ago
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