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Xelga [282]
3 years ago
11

Which element has the valence configuration 6s26p2 ?

Chemistry
2 answers:
blagie [28]3 years ago
8 0
For the answer to the question above,
The period six on the periodic table starts the row after Xenon. The electron Shell <span>6s2 6p2 corresponds to the atomic number 82 and this element is <u>LEAD.
</u>I hope my answer helped you</span>
Fittoniya [83]3 years ago
4 0
The correct answer is the element FE hope i helped the Champion out!
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Predict whether the equilibria I) CH4(g) + H2O(g) ⇀↽ CO(g) + 3 H2(g), ∆H◦ = +206 kJ II) 2 SO2(g) + O2 ⇀↽ 2 SO3(g), ∆H◦ = −198 kJ
Dima020 [189]

Answer:

(1) I shifts toward product and II shifts toward reactant.

Explanation:

Increasing the temperature of an endothermic reaction (∆H is positive) shifts the equilibrium position to the right thus favoring product formation.

Increasing the temperature of an exothermic reaction (∆H is negative) shifts the equilibrium position to the left thus favoring the backward reaction.

3 0
3 years ago
How are Ionic and Covalent Bonds are formed with examples ?
Helga [31]

Answer:Comparison of Ionic and Covalent Bonds

In an ionic bond, the atoms are bound together by the electrostatic forces in the attraction between ions of opposite charge. ... For example, sodium (Na), a metal, and chloride (Cl), a nonmetal, form an ionic bond to make NaCl. In a covalent bond, the atoms bond by sharing electrons.

     

pls   add  Brainliest

7 0
3 years ago
You have 2.394 x 102 mL of oxygen gas (O2) at 7.20 x 102 mm of Hg and 78 oC.
igomit [66]
We are given with
V = <span>2.394 x 102 mL 
P = </span><span>7.20 x 102 mm of Hg
T = </span><span>78 oC

We are asked to determine the mass of the sample in milligrams
Using the ideal gas law
n = PV / RT
n = </span>7.20 x 102 mm of Hg (2.394 x 102 mL) / R (78 + 273)
Use the appropriate value for R or just convert the values to SI and use R = 8.314
Then, solve for the mass of the sample by using the MW Oxygen which is 16 g/mol
3 0
3 years ago
I need help solving this!
zmey [24]

Answer: Moles of hydrogen required are 4.57 moles to make 146.6 grams of methane, CH_{4}.

Explanation:

Given: Mass of methane = 146.6 g

As moles is the mass of a substance divided by its molar mass. So, moles of methane (molar mass = 16.04 g/mol) are calculated as follows.

Moles = \frac{mass}{molar mass}\\= \frac{146.6 g}{16.04 g/mol}\\= 9.14 mol

The given reaction equation is as follows.

C + 2H_{2} \rightarrow CH_{4}

This shows that 2 moles of hydrogen gives 1 mole of methane. Hence, moles of hydrogen required to form 9.14 moles of methane is as follows.

Moles of H_{2} = \frac{9.14}{2}\\= 4.57 mol

Thus, we can conclude that moles of hydrogen required are 4.57 moles to make 146.6 grams of methane, CH_{4}.

5 0
3 years ago
Gold’s natural state has a definite shape and a definite volume. What is gold’s natural state(s)?
Mekhanik [1.2K]

Answer:

Solid

Explanation:

6 0
3 years ago
Read 2 more answers
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