F(x) = 3x + 1
let f(x) = y
y = 3x + 1
y - 1 = 3x
3x = y - 1
x = (y - 1)/3
From y = f(x), x = f⁻¹(y)
<span>x = (y - 1)/3
</span>
f⁻¹(y) = (y - 1)/3
f⁻¹(7) = <span>(7 - 1)/3 = 6/3 = 2
</span>f⁻¹(7)<span> = 2</span>
Y = 3x + 4
y = 3x + 7
3x + 4 = 3x + 7
3x - 3x = 7 - 4
0 = 3.....incorrect....this system has no solutions because ur lines are parallel and they never cross.
or look at it this way..
y = 3x + 4
y = 3x + 7
both have slopes of 3...but the y intercepts are different......when this happens, it means the lines are parallel with no solution
It's a linear function. We need only two points to draw a graph.
We choose any values of x and calculate the value of y.
for x= 0 → y = 3(0) - 1 = 0 - 1 = -1 → (0, -1)
for x = 2 → y = 3(2) - 1 = 6 - 1 = 5 → (2, 5)
for x = 0 → y = 3(0) - 1/3 = 0 - 1/3 = -1/3 → (0, -1/3)
for x = 2 → y = 3(2) - 1/3 = 6 - 1/3 = 5 2/3 → (2, 5 2/3)
The error to that problem is the person switched the x and y points, like in point A, it’s supposed to be (x,y) or (1,5). The person put the y in front of the x while writing the points.
Answer:
the triangle above is an isoceles triangle
therefore the base angles are equal
So we have:
X + X + 38= 180
2x = 180-38
2x = 142
X = 71°
