Answer: No, Sid divided by 100 correctly
Step-by-step explanation:
Surface Area of Cylinder
The circumference of the base is 5.7
Step-by-step explanation:
The lateral surface of an object is defined as the area of all the sides of the object, excluding the area of its base and top.
A cylinder has two faces, two curved edges where the curved wall meets the end circles, and a curved surface stretching between the two circular ends.
For a cylinder, the lateral surface area is the curved surface that connects the base and the top.
The lateral surface area ![A_{L} = 2\pi rh\\](https://tex.z-dn.net/?f=A_%7BL%7D%20%20%3D%20%202%5Cpi%20rh%5C%5C)
where r is radius of the base of the cylinder
and h is height of the cylinder
and
is 3.14
The circumference of the base of cylinder = C
where C = ![2\pi r\\](https://tex.z-dn.net/?f=2%5Cpi%20r%5C%5C)
Given
= 34 and h = 6
⇒
= C × h
⇒
⇒ C =
= 5.7
Hence the circumference of the base of the cylinder is 5.7
Answer:
![P+Q=5x^2+4](https://tex.z-dn.net/?f=P%2BQ%3D5x%5E2%2B4)
![Q-P=-x^2-4x+16](https://tex.z-dn.net/?f=Q-P%3D-x%5E2-4x%2B16)
Step-by-step explanation:
We are given
![P=3x^2+2x-6](https://tex.z-dn.net/?f=P%3D3x%5E2%2B2x-6)
![Q=2x^2-2x+10](https://tex.z-dn.net/?f=Q%3D2x%5E2-2x%2B10)
Calculation of P+Q:
![P+Q=3x^2+2x-6+2x^2-2x+10](https://tex.z-dn.net/?f=P%2BQ%3D3x%5E2%2B2x-6%2B2x%5E2-2x%2B10)
now, we can combine like terms
![P+Q=3x^2+2x^2+2x-2x+10-6](https://tex.z-dn.net/?f=P%2BQ%3D3x%5E2%2B2x%5E2%2B2x-2x%2B10-6)
![P+Q=5x^2+0+4](https://tex.z-dn.net/?f=P%2BQ%3D5x%5E2%2B0%2B4)
![P+Q=5x^2+4](https://tex.z-dn.net/?f=P%2BQ%3D5x%5E2%2B4)
Calculation of Q-P:
![Q-P=2x^2-2x+10-(3x^2+2x-6)](https://tex.z-dn.net/?f=Q-P%3D2x%5E2-2x%2B10-%283x%5E2%2B2x-6%29)
Firstly, we will distribute negative sign
![Q-P=2x^2-2x+10-3x^2-2x+6](https://tex.z-dn.net/?f=Q-P%3D2x%5E2-2x%2B10-3x%5E2-2x%2B6)
now, we can combine like terms
![Q-P=2x^2-3x^2-2x-2x+6+10](https://tex.z-dn.net/?f=Q-P%3D2x%5E2-3x%5E2-2x-2x%2B6%2B10)
![Q-P=-x^2-4x+16](https://tex.z-dn.net/?f=Q-P%3D-x%5E2-4x%2B16)
More than 2 because the length of the line opposite to the the obtuse angle can be any length