Answer: i - j - k
Step-by-step explanation:
Taking the cross product between two vectors will give you a third vector that is orthogonal(perpendicular) to both vectors.
<1,1,0> x <1,0,1>
![det(\left[\begin{array}{ccc}i&j&k\\1&1&0\\1&0&1\end{array}\right] )](https://tex.z-dn.net/?f=det%28%5Cleft%5B%5Cbegin%7Barray%7D%7Bccc%7Di%26j%26k%5C%5C1%261%260%5C%5C1%260%261%5Cend%7Barray%7D%5Cright%5D%20%29)
the determinate of the matrix: <1,-(1),-1>
or: i - j - k
.4 × 2.5 = 1. product means multiply / sum would be addition
Answer:
Step-by-step explanation:
We know a triangle adds up to 180 so:
75+36+ ? = 180
111+ ? =180
? = 69
To find out x, we know that a straight line adds up to 180 so again:
x +69 = 180
x = 111
The answer would be 20 over 1 bevause if you do 20 ×1 you get 20. So the would be 20 over 1.
X+x+1+x+2=51
3x+3=51
Use inverse operations to solve
subtract 3 from both sides
3x=48
Divide by 3 on both sides
x=16
16, 17, 18
