Distance =

so plug in the coordinates and you will get 14.14 units
Answer:
Yes
Step-by-step explanation:
First, suppose that nothing has changed, and possibility p is still 0.56. It's our null hypothesis. Now, we've got Bernoulli distribution, but 30 is big enough to consider Gaussian distribution instead.
It has mean μ= np = 30×0.56=16.8
standard deviation s = √npq
sqrt(30×0.56×(1-0.56)) = 2.71
So 21 is (21-16.8)/2.71 = 1.5494 standard deviations above the mean. So the level increased with a ˜ 0.005 level of significance, and there is sufficient evidence.
Answer:
1)
- Greater than -10 and less than 10.
2)
- Greater than or equal to -10 and less than or equal to 10.
3)
- Greater than or equal to -10 and less than 10.
4)
Greater than -10 and less than or equal to 10.
Step-by-step explanation:
There are four form of describing that set in interval notation, which presented below:
1)
- Greater than -10 and less than 10.
2)
- Greater than or equal to -10 and less than or equal to 10.
3)
- Greater than or equal to -10 and less than 10.
4)
Greater than -10 and less than or equal to 10.
Given, arc QR is congruent to arc LN and arc OP is congruent to arc VW.
And the expressions for each arc in the diagram also given as:
Arc QR = 2x - y, arc LN = 11 , arc OP= 10 and arc VW=5x+y.
Hence, we will get the system of equations as following:
Arc QR = Arc LN
2x - y = 11 ...(1)
Arc OP = Arc VW
5x + y = 10 ...(2)
We need to find the value of x. So, we can add the equations to eliminate y so that we can solve the equations for x. Therefore,
2x+5x = 11 + 10
7x = 21
Divide each sides by 7.
So, x= 3