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3 years ago

Solve for x. (Similar Triangles)

Mathematics

1 answer:

Softa [21]3 years ago

3 0

Answer:

x = 1

Step-by-step explanation:

its a special right trianlge. So both sides are the same.

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A Florida poll asked 1200 Floridians whether they would prefer an increase in taxes or a decrease in government services as a wa

mojhsa [17]

Answer:

Step-by-step explanation:

Given that a lorida poll asked 1200 Floridians whether they would prefer an increase in taxes or a decrease in government services as a way to balance the budget.

$H_0: p =0.50\\H_a: p >0.50\\$

(Right tailed test)

STd error assuming H0 to be true = $\sqrt{pq/n} =0.0144$ for n =1200

Mean difference =0.02

Test statistic =1.386

p value = 0.0823

5) If n =2500, std error would be = 0.01

Test statistic Z = 2

p value = 0.25

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2 years ago

Find the value of x 2x + 46 = 7x + 6

maria [59]

Answer:

<h3>hope it helps .........</h3>

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3 years ago

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How many times does 8 go into 60??? i cant remember even if it does

Anit [1.1K]

It goes in it 7.5 times

4 0

3 years ago

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Use the given values of n and p to find the minimum usual value μ−2σ and the maximum usual value μ+2σ. Round to the nearest hund

lbvjy [14]

Answer:

μ−2σ = 1,089.26

μ+2σ = 1,097.62

Step-by-step explanation:

The standard deviation of a sample of size 'n' and proportion 'p' is:

$\sigma=\sqrt{\frac{p*(1-p)}{n} }$

If n=1139 and p =0.96, the standard deviation is:

$\sigma=\sqrt{\frac{p*(1-p)}{n}}\\\sigma = 0.001836$

The minimum and maximum usual values are:

$\mu-2\sigma = (p-2\sigma)*n\\\mu+2\sigma = (p+2\sigma)*n$

$\mu-2\sigma = (0.96-2*0.001836)*1139\\\mu-2\sigma = 1,089.26\\\mu+2\sigma = (0.96+2*0.001836)*1139\\\mu+2\sigma = 1,097.62$

5 0

2 years ago

What is √-11 in the form a+bi?

Mice21 [21]

Given:

The number is $\sqrt{-11}$ .

To find:

The a+bi form of given number.

Solution:

We have,

$\sqrt{-11}$

It can be written as

$\sqrt{-11}=\sqrt{-1\times 11}$

$\sqrt{-11}=\sqrt{-1}\times \sqrt{11}$ $[\because \sqrt{ab}=\sqrt{a}\sqrt{b}]$

$\sqrt{-11}=i\times \sqrt{11}$ $[\because \sqrt{-1}=i]$

$\sqrt{-11}=\sqrt{11}i$

Here, real part is missing. So, it can be taken as 0.

$\sqrt{-11}=0+\sqrt{11}i$

So, a = 0 and $b=\sqrt{11}$ .

Therefore, the a+bi form of given number is $0+\sqrt{11}i$ .

5 0

2 years ago