1answer.
Ask question
Login Signup
Ask question
All categories
  • English
  • Mathematics
  • Social Studies
  • Business
  • History
  • Health
  • Geography
  • Biology
  • Physics
  • Chemistry
  • Computers and Technology
  • Arts
  • World Languages
  • Spanish
  • French
  • German
  • Advanced Placement (AP)
  • SAT
  • Medicine
  • Law
  • Engineering
aleksandr82 [10.1K]
2 years ago
15

Find the angles ab pls hurry

Mathematics
1 answer:
Andrei [34K]2 years ago
3 0

Answer:

HMMMMMMMMMMMMMMMMMMMMMMMMMMMMMMMMMMMMMMMMm

Step-by-step explanation:

You might be interested in
Can someone help me with this
jarptica [38.1K]

The answer is:

x=-8

Because:

If you pick a number(-8) to fill in the equation written below

5x+20+5x=5x-20

After applying the -8 to x you get

-40+20-40=-40-20

When you simply the both sides you get

-60=-60

And that’s right -60 is equal to -60!

5 0
3 years ago
Read 2 more answers
Suppose you are working in an insurance company as a statistician. Your manager asked you to check police records of car acciden
pochemuha

Answer:

(a) 95% confidence interval for the percentage of all car accidents that involve teenage drivers is [0.177 , 0.243].

(b) We are 95% confident that the percentage of all car accidents that involve teenage drivers will lie between 17.7% and 24.3%.

(c) We conclude that the the percentage of teenagers has not changed since you join the company.

(d) We conclude that the the percentage of teenagers has changed since you join the company.

Step-by-step explanation:

We are given that your manager asked you to check police records of car accidents and out of 576 accidents you selected randomly, teenagers were at the wheel in 120 of them.

(a) Firstly, the pivotal quantity for 95% confidence interval for the population proportion is given by;

                        P.Q. = \frac{\hat p-p}{\sqrt{\frac{\hat p(1-\hat p)}{n} }}  ~ N(0,1)

where, \hat p = sample proportion teenage drivers = \frac{120}{576} = 0.21

           n = sample of accidents = 576

           p = population percentage of all car accidents

<em>Here for constructing 95% confidence interval we have used One-sample z proportion statistics.</em>

So, 95% confidence interval for the population population, p is ;

P(-1.96 < N(0,1) < 1.96) = 0.95  {As the critical value of z at 2.5% level

                                                     of significance are -1.96 & 1.96}  

P(-1.96 < \frac{\hat p-p}{\sqrt{\frac{\hat p(1-\hat p)}{n} }} < 1.96) = 0.95

P( -1.96 \times {\sqrt{\frac{\hat p(1-\hat p)}{n} }} < {\hat p-p} < 1.96 \times {\sqrt{\frac{\hat p(1-\hat p)}{n} }} ) = 0.95

P( \hat p-1.96 \times {\sqrt{\frac{\hat p(1-\hat p)}{n} }} < p < \hat p+1.96 \times {\sqrt{\frac{\hat p(1-\hat p)}{n} }} ) = 0.95

<u>95% confidence interval for p</u> = [\hat p-1.96 \times {\sqrt{\frac{\hat p(1-\hat p)}{n} }} , \hat p+1.96 \times {\sqrt{\frac{\hat p(1-\hat p)}{n} }}]

  = [ 0.21-1.96 \times {\sqrt{\frac{0.21(1-0.21)}{576} }} , 0.21+1.96 \times {\sqrt{\frac{0.21(1-0.21)}{576} }} ]

  = [0.177 , 0.243]

Therefore, 95% confidence interval for the percentage of all car accidents that involve teenage drivers is [0.177 , 0.243].

(b) We are 95% confident that the percentage of all car accidents that involve teenage drivers will lie between 17.7% and 24.3%.

(c) We are also provided that before you were hired in the company, the percentage of teenagers who where involved in car accidents was 18%.

The manager wants to see if the percentage of teenagers has changed since you join the company.

<u><em>Let p = percentage of teenagers who where involved in car accidents</em></u>

So, Null Hypothesis, H_0 : p = 18%    {means that the percentage of teenagers has not changed since you join the company}

Alternate Hypothesis, H_A : p \neq 18%    {means that the percentage of teenagers has changed since you join the company}

The test statistics that will be used here is <u>One-sample z proportion statistics</u>;

                              T.S.  =  \frac{\hat p-p}{\sqrt{\frac{\hat p(1-\hat p)}{n} }}  ~ N(0,1)

where, \hat p = sample proportion teenage drivers = \frac{120}{576} = 0.21

           n = sample of accidents = 576

So, <u><em>test statistics</em></u>  =  \frac{0.21-0.18}{\sqrt{\frac{0.21(1-0.21)}{576} }}  

                              =  1.768

The value of the sample test statistics is 1.768.

Now at 0.05 significance level, the z table gives critical value of -1.96 and 1.96 for two-tailed test. Since our test statistics lies within the range of critical values of z, so we have insufficient evidence to reject our null hypothesis as it will not fall in the rejection region due to which <u>we fail to reject our null hypothesis</u>.

Therefore, we conclude that the the percentage of teenagers has not changed since you join the company.

(d) Now at 0.1 significance level, the z table gives critical value of -1.6449 and 1.6449 for two-tailed test. Since our test statistics does not lie within the range of critical values of z, so we have sufficient evidence to reject our null hypothesis as it will fall in the rejection region due to which <u>we reject our null hypothesis</u>.

Therefore, we conclude that the the percentage of teenagers has changed since you join the company.

4 0
3 years ago
You decide to make this recipe a week later, but this time you find out that you
NISA [10]

Answer: 1.5 divided by 2= 0.75

7 0
3 years ago
Read 2 more answers
5(2z-2)=9(z+2) how to solve it
IceJOKER [234]

Answer:

z=28

Step-by-step explanation:

10z-10=9z+18

-9z        -9z

z-10=18

+10   +10

z=28

7 0
3 years ago
8(2x-6)=96 solve the equation
Mandarinka [93]

Answer:

x=9

Step-by-step explanation:

8(2x-6)=96

2x-6=96/8

2x-6=12

2x=12+6

2x=18

x=18/2

x=9

7 0
3 years ago
Read 2 more answers
Other questions:
  • for a function, can the number of elements in the range be greater than the number of elements in the domain? explain.
    7·2 answers
  • A store had 100 t-shirts. each month, 30% of the t-shirts were sold and 25 new t-shirts arrived in shipments. which recursive fu
    8·2 answers
  • Solve the following inequality: –1 &gt; –2(x – 4) – 5(4x – 7).
    11·1 answer
  • what are the lower, middle and upper quartiles of this data 122, 164, 71, 98, 147, 114, 111, 98, 85, 104, 71, 77
    11·2 answers
  • Solve the equation.<br><br> y + 3 = –y + 9<br><br> y = 1<br> y = 3<br> y = 6<br> y = 9
    7·2 answers
  • The last question is not 3.6
    9·1 answer
  • I don’t understand!!!
    5·1 answer
  • If x+z=15 and w + y =10, what is the value of (3w+3y)(2x+2z)?
    5·2 answers
  • Options of Answer
    8·1 answer
  • For what value(s) of the constant b does the equation f(x)=3x^2+bx+27 have 1 x-intercept
    6·1 answer
Add answer
Login
Not registered? Fast signup
Signup
Login Signup
Ask question!