Question

-1/225x^2+2/3x what is the vertex of this quadratic function?

Answer 1

$\bf \textit{vertex of a parabola}\\ \quad \\\\ \begin{array}{lccclll} y=&-\frac{1}{225}x^2&+\frac{2}{3}x\\\\ y=&-\frac{1}{225}x^2&+\frac{2}{3}x&+0\\ &\uparrow &\uparrow &\uparrow \\ &a&b&c \end{array}\qquad \left(-\cfrac{{{ b}}}{2{{ a}}}\quad ,\quad {{ c}}-\cfrac{{{ b}}^2}{4{{ a}}}\right)$