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tamaranim1 [39]
3 years ago
8

Please help me [Below is the graph of equation y=|x+2|-1. Use this graph to find all values of x such that y<0] IF YOU PUT A

LINK OR UNHELPFUL ANSWER I WILL REPORT YOU, I GIVE BRAINLIEST

Mathematics
1 answer:
Alchen [17]3 years ago
3 0

Answer:

x ∈ (-3, -1)

Step-by-step explanation:

In the graph, the vertical axis represents the y-value, while the horizontal axis represents the x-value.

y < 0 (y smaller than zero) happens in the region where the graph is below the horizontal axis.

Only by looking at the graph, we can see that y < 0 (the graph is below the horizontal axis) for the values of x in the interval (-3, -1)

Then all the values of x such that y < 0 are:

x ∈ (-3, -1)

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Rewrite in logarithmic form 19^2 = 361
Aneli [31]

Answer:

  \log_{19}{361}=2

Step-by-step explanation:

We know that taking logarithms performs the transformation ...

  b^e=x\\\\e\cdot\log{b}=\log{x}\quad\text{take logs}\\\\e=\dfrac{\log{x}}{\log{b}}\quad\text{divide by $\log{b}$}\\\\\log_b{x}=e\quad\text{use the change of base formula}

Then for b=19, e=2, x=361, we have

  \boxed{\log_{19}{361}=2}

8 0
3 years ago
What is the answer to this question
julia-pushkina [17]
I hope this helps you



Formula => I=PRT


900=7500.R.2


R=900/15000


R=0,06



3 0
3 years ago
Use the graph of the function. Determine Over what interval(s) the function is positive or negative.
soldier1979 [14.2K]

Answer:

please where is the drawing I mean the graph

6 0
3 years ago
a recipe calls for 2 cups of flour for every 3 cups of sugar. If you are planning to use 5 cups of flour, how many cups of sugar
riadik2000 [5.3K]

Answer:

7½ cups of sugar

Step-by-step explanation:

2 cups of flour needs 3 cups of sugar

1 cups of flour needs 3/2=1.5 cups of sugar

1×5 cups of flour needs 1.5×5=7.5 cups of sugar=7½ cups of sugar ANS

3 0
2 years ago
Simplify the expression using trigonometric identities:
Anastaziya [24]

The simplified expression is the one in option B.

<h3>How to simplify the expression?</h3>

Remember that:

sec(x) = 1/cos(x)\\\\cos(x) = cos(-x)

With these two, we can rewrite the numerator as:

sec(x)*sin(-x) + tan(-x)\\\\\frac{1}{cos(x)}*sin(-x) + tan(x)\\\\\frac{1}{cos(-x)}*sin(-x) + tan(-x)\\\\2*tan(-x)

Replacing that in the given expression, we have:

\frac{2*tan(-x)}{1 + sec(-x)} = \frac{2*tan(-x)}{1 + 1/cos(-x)}

Now, if we multiply and divide by cos(-x), we get:

\frac{2*tan(-x)}{1 + 1/cos(-x)} =  \frac{2*tan(-x)}{1 + 1/cos(-x)}*\frac{cos(-x)}{cos(-x)} \\\\= \frac{2*sin(-x)}{1 + cos(-x)}

Now remember that:

cos(x) = cos(-x)\\sin(-x) = -sin(x)

With these two properties:

\frac{2*sin(-x)}{1 + cos(-x)} = \frac{-2*sin(x)}{1 + cos(x)}

Then the correct option is B.

If you want to learn more about trigonometric identities:

brainly.com/question/7331447

#SPJ1

3 0
2 years ago
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