The given area of the 
ft. by 33 ft. wall less the areas of the Windows and the Door give the area of the painted part of the wall as 
ft.²
<h3>How can the area of the painted part be calculated?</h3>
The area of the painted part of the wall is ft.²
The given dimensions of the wall are;
The width of the wall = ft.
The height of the wall = 33 ft.
The painted area = Area of the wall - (Area of the widows + The door)
Which gives;
The area of the painted part of the wall is ft.²
Learn more about the area of a rectangle here:
brainly.com/question/18101587
Answer:
You did not post the options, but i will try to answer this in a general way.
Because we have two solutions, i know that we are talking about quadratic equations, of the form of:
0 = a*x^2 + b*x + c.
There are two easy ways to see if the solutions of this equation are real or not.
1) look at the graph, if the graph touches the x-axis, then we have real solutions (if the graph does not touch the x-axis, we have complex solutions).
2) look at the determinant.
The determinant of a quadratic equation is:
D = b^2 - 4*a*c.
if D > 0, we have two real solutions.
if D = 0, we have one real solution (or two real solutions that are equal)
if D < 0, we have two complex solutions.
The
questions asked to name a particular points that contains x and y
coordinates.
<span>
distance = (x -(-1))2 + (y -5)2 = 2
distance = </span><span>(x +1))2 + (y -5)2 = 2
</span><span> => (√(2)
-1,5)
=> (-1, 5 + </span>√ <span>(2)
=> (0, 4)
=>
(0, 6)</span><span>Thus, here are
the lists of possible points. (0, 4) and (0, 6).
</span>
7/8 * 1/2+ 7/16
if not 1/8
