Ask question

Ask question

All categories

3 years ago

15

A kangaroo hops 2 kilometers in 3 minutes at this rate a. how long does it take the kangaroo to travel 5 kilometers b. how far d

oes the kangaroo travel in 2 minutes

1 answer:

spin [16.1K]3 years ago

8 0

Answer:

7.5

Step-by-step explanation:

You might be interested in

Assume the rate of inflation is 8% per year for the next 2 years. What will be the cost of goods 2 years from now, adjusted fo

Paha777 [63]

<h3>Answer: $326.59</h3>

==============================================

Work Shown:

F = future value

P = present value = 280

r = rate of inflation in decimal form = 0.08

t = elapsed time in years = 2

---------

F = P*(1+r)^t

F = 280*(1+0.08)^2

F = 326.592

F = 326.59

8 0

3 years ago

PLS HELP AS SOON AS YOU CAN!!!....

N76 [4]

Answer:

I would say B because there are 15 1s

5 0

4 years ago

An author receives a contract from a publisher, according to which she is to be paid a fixed sum of $20,000 plus $3.50 for each

Schach [20]

Answer:

The mean of the total payments she will receive is $79,500.

The standard deviation of the total payments she will receive is $14,000.

Step-by-step explanation:

Given : An author receives a contract from a publisher, according to which she is to be paid a fixed sum of $20,000 plus $3.50 for each copy of her book sold. The author judges that her uncertainty about total sales of the book can be represented by a random variable with a mean of 17,000 and a standard deviation of 4,000 books.

To find : The mean and standard deviation of the total payments she will receive ?

Solution :

Let 'x' represent total sales of the book.

Let 'y' represent the payment to the author.

According to question,

The mean of the total payments she will receive is given by,

$\mu_y=20,000+3.50\mu_x$

Where, $\mu_x=17,000$

Substitute in the equation,

$\mu_y=20000+3.50\times 17000$

$\mu_y=20000+59500$

$\mu_y=79500$

The mean of the total payments she will receive is $79,500.

The standard deviation of the total payments she will receive is given by,

$\sigma_y=|3.50|\sigma_x$

Where, $\sigma_x=4,000$

Substitute in the equation,

$\sigma_y=|3.50|\times 4000$

$\sigma_y=14000$

The standard deviation of the total payments she will receive is $14,000.

7 0

3 years ago

Find the f^-1(x) and it’s domain

borishaifa [10]

Answer:

$f^{-1}(x) = (x + 8)^2$

$x \ge -8$

Step-by-step explanation:

Given

$f(x) = \sqrt x - 8$

Solving (a): $f^{-1}(x)$

We have:

$f(x) = \sqrt x - 8$

Express f(x) as y

$y = \sqrt x - 8$

Swap x and y

$x = \sqrt y - 8$

Add 8 to $both\ sides$

$x + 8 = \sqrt y - 8 + 8$

$x + 8 = \sqrt y$

Square both sides

$(x + 8)^2 = y$

Rewrite as:

$y = (x + 8)^2$

Express y as: $f^{-1}(x)$

$f^{-1}(x) = (x + 8)^2$

To determine the domain, we have:

The original function is $f(x) = \sqrt x - 8$

The range of this is: $f(x) \ge -8$

The $domain$ of the $inverse$ function is the $range$ of the $original$ function.

<em>Hence, the domain is:</em>

$x \ge -8$

3 0

3 years ago

Approximate the integral integral integral integral f(x, y) dA by dividing the rectangle R with vertices (0, 0), (4, 0), (4, 2),

amm1812

Answer:

Step-by-step explanation:

Approximate the integral $\int\int\limits_R {f(x,y)} \, dA$ by dividing the region $R$ with vertices (0,0),(4,0),(4,2) and (0,2) into eight equal squares.

Find the sum $\sum\limits^8_{i=1}f(x_i,y_i)\delta A_i$

Since all are equal squares, so $\delta A_i=1$ for every $i$

$\sum\limits^8_{i=1}f(x_i,y_i)\delta A_i=f(x_1,y_1)\delta A_1+f(x_2,y_2)\delta A_2+f(x_3,y_3)\delta A_3+f(x_4,y_4)\delta A_4+f(x_5,y_5)\delta A_5+f(x_6,y_6)\delta A_6+f(x_7,y_7)\delta A_7+f(x_8,y_8)\delta A_8\\\\=f(0.5,0.5)(1)+f(1.5,0.5)(1)+f(2.5,0.5)(1)+f(3.5,0.5)(1)+f(0.5,1.5)(1)+f(1.5,1.5)(1)+f(2.5,1.5)(1)+f(3.5,1.5)(1)\\\\=0.5+0.5+1.5+0.5+2.5+0.5+3.5+0.5+0.5+1.5+1.5+1.5+2.5+1.5+3.5+1.5\\\\=24$

Thus, $\sum\limits^8_{i=1}f(x_i,y_i)\delta A_i=24$

Evaluating the iterate integral $\int\limits^4_0 \int\limits^2_0 {(x+y)} \, dydx=\int\limits^4_0 {[xy+\frac{y^2}{2} ]}\limits^2_0 \, dx =\int\limits^4_0 {[2x+2]}dx\\\\=[x^2+2x]\limits^4_0=24.$

Thus, $\int\limits^4_0 \int\limits^2_0 {(x+y)} \, dydx=24$

7 0

3 years ago