To solve for x, you need to isolate/get the variable "x" by itself in the equation:
3x - 3(x + 1) = 3 Distribute/multiply -3 into (x + 1)
3x + (-3)x + (-3)1 = 3
3x - 3x + 1 = 3
1 = 3
Your answer is no solution because the variable "x" is canceled out and 1 ≠ 3
Answer:
<u>∗ = 0.4x³</u>
Step-by-step explanation:
(15y + ∗)² = 225y²+12x³y+0.16x⁶
<u>Note:</u>
225y² = 15y * 15y = (15y)²
12x³y = 2 * 15y * 0.4x³
0.16x⁶ = 0.4x³ * 0.4x³ = (0.4x³)²
So, by factoring the right hand side:
225y²+12x³y+0.16x⁶ = (15y + 0.4x³)²
By comparing the left hand side with (15y + 0.4x³)²
<u>So, ∗ should be replaced with the monomial 0.4x³</u>
Elimination would be the best
