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hammer [34]
3 years ago
6

Show and/or explain why (1/3)^3 = 1/27​

Mathematics
2 answers:
gizmo_the_mogwai [7]3 years ago
5 0
(1/3)^3 = (1/3)*(1/3)*(1/3)

When you multiply fractions, you multiply all the numerators and all the denominators. Since the numerator is just 1, 1*1*1=1. The denominator is 3, and 3*3=9, 9*3=27. Therefore, 1/27.
ratelena [41]3 years ago
4 0
(1)^3 /(3)^3
(1x1x1)/{3x3x3}
1/27 hope it helps :))
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Consider a Triangle ABC like the one below. Suppose that C = 98, A = 74, and b = 11 (figure is not drawn to scale.) solve the tr
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Answer:

A=73.8\°

B=8.2\°

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Step-by-step explanation:

step 1

Find the measure of side c

Applying the law of cosines

c^{2}= a^{2}+b^{2}-2(a)(b)cos(C)

substitute the given values

c^{2}= 74^{2}+11^{2}-2(74)(11)cos(98\°)

c^{2}=5,823.5738

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step 2

Find the measure of angle A

Applying the law of sine

\frac{a}{sin(A)}=\frac{c}{sin(C)}

substitute the given values

\frac{74}{sin(A)}=\frac{76.3}{sin(98\°)}

sin(A)=(74)sin(98\°)/76.3

A=arcsin((74)sin(98\°)/76.3)

A=73.8\°

step 3

Find the measure of angle B

we know that

The sum of the internal angles of a triangle must be equal to 180 degrees

so

A+B+C=180\°

substitute the given values

73.8\°+B+98\°=180\°

171.8\°+B=180\°

B=180\°-171.8\°=8.2\°

5 0
3 years ago
A water trough is 7 m long and has a cross-section in the shape of an isosceles trapezoid that is 30 cm wide at the bottom, 70 c
valentina_108 [34]

Answer:

The degree of fastness by which the water is rising is 210 seconds

Step-by-step explanation:

The volume of the trough when the water depth is 20 cm is first calculated

Volume of the trough (Trapezoidal Prism) = LH (A + B) × 0.5

Where L is the length of the trough, H is the height of the trough and A and B are parallel width of the top and bottom of the trough

Volume of the trough = 7 × 0.2 (0.3 + 0.7) × 0.5 = 0.7m³

The fastness at which the water is rising is = Volume ÷ water flow rate = 0.7 ÷ 0.2 = 3.5 min = 210 seconds

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3 years ago
Read 2 more answers
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