F(x)=6x^4-10x^3+40x-50, plug 2 in for x
f(2)=6(2)^4-10(3)^3+40(2)-50
f(2)=12^4-30^3+80-50
f(2)=20735-27,000+80-50
f(2)=-6,235
Yes you are right! There is much more balance in the left than in the right!
It's 4. The factors of 12 are: 1,2,3,4,6,12. The factors of 20 are: 1,2,4,5,10,20.
Answer:
x < 3 and x > -1
Step-by-step explanation:
Step 1: Subtract 2 from both sides.
Step 2: Solve absolute value.
- We know x - 1 < 2 and x - 1 > -2.
Condition 1:
Condition 2:
Therefore, the answer is x < 3 and x > -1.
Answer:
3.
Step-by-step explanation:
Find the midpoint of BC:
midpoint = (-1+5)/2, (2-2)/2 = (2, 0).
The slope of BC = (2 - -2) / (-1-5) = -2/3.
Find the equation of the right bisector of BC:
The slope = -1 / -2/3 = 3/2.
y-y1 = m(x-x1)
y - 0 = 3/2(x - 2)
y = 3/2x - 3.
Now find the equation of the median through C:
The midpoint of AB = (1 - 1)/2, (4+2)/2
= (0, 3).
The equation of the median:
The slope = (-2-3) / (5-0)
= -1.
The equation is:
y - 3 = -1(x - 0)
y -3 = -x.
Now we find the point of intersection by solving the 2 equations:
y - 3 = -x
y = 3/2x - 3
y = -x + 3
So:
3/2x - 3 = -x + 3
3/2x + x = 6
5/2 x = 6
x = 12/5.
y = -12/5 + 3
= -12/5 + 15/5
= 3/5.
The sum of the coordinates = 12/5 + 3 /5
= 15/5
= 3.
(Add 1 to both sides)
(Add 1 to both sides)