3 years ago

40+40x0+1= a.81 b.21 c.41

Mathematics

1 answer:

inn [45]3 years ago

5 0

Answer:

C.41

Step-by-step explanation:

Thats the answer!!

You might be interested in

Figure I has 1 dot, Figure 2 has 3 dots, Figure 3 has 5 dots etc... The pattern is +1 +2 +3 etc. If the pattern goes on. What wo

AleksandrR [38]

The 100th figure has 201 dots :)

3 0

3 years ago

Anybody know the right answer?

qwelly [4]

Quadrant I : cot(x) > 0 → -cot(x) < 0

Quadrant II : cot(x) < 0 → -cot(x) > 0

Quadrant III : cot(x) > 0 → -cot(x) < 0

Quadrant IV : cot(x) < 0 → -cot(x) > 0

------------------------------------------------------------------

$a)\ \left(\dfrac{11\pi}{6},\ -\sqrt3\right)\\\\\dfrac{11\pi}{6}\in\text{Quadrant IV, then -cot(x)} > 0,\ \text{we have}\ -\cot\dfrac{11\pi}{6}=-\sqrt3 < 0$

Answer: a)

$b)\\\dfrac{2\pi}{3}\in\text{Quadrant II},\ -\cot(x) > 0,\ \text{we have}\ \dfrac{\sqrt3}{3} > 0\\\\c)\\\dfrac{5\pi}{4}\in\text{Quadrant III},\ -\cot(x) < 0,\ \text{we have}\ -1 < 0\\\\d)\\\dfrac{4\pi}{3}\in\text{Quadrant III},\ -\cot(x) < 0,\ \text{we have}\ -\dfrac{\sqrt3}{3} < 0$