Answer:
The answer is "
".
Step-by-step explanation:
Given value:
4 40 32
Solution:
If we divide the value by 4 it will give 10 and 8.
If we add the boxed value it will be equal to 72 and divide the value by 4 it will give a value 18.
Convert the mixed number <span><span>8<span>34</span></span><span>8<span>34</span></span></span> into an improper fraction first by multiplying the denominator (<span>44</span>) by the whole number part (<span>88</span>) and add the numerator (<span>33</span>) to get the new numerator. Place the new numerator (<span>3535</span>) over the old denominator (<span>44</span>).<span><span>354</span><span>354</span></span>The result can be shown in both exact and decimal forms.Exact Form:<span><span>354</span><span>354</span></span>Decimal Form:<span>8.758.75</span>Mixed Number Form:<span>8<span><span>34 </span></span></span>
The work done (in foot-pounds) in stretching the spring from its natural length to 0.7 feet beyond its natural length is 1.23 foot-pound
<h3>Data obtained from the question</h3>
From the question given above, the following data were obtained:
- Force (F) = 3 pounds
- Extension (e) = 0.6 feet
- Work done (Wd) =?
<h3>How to determine the spring constant</h3>
- Force (F) = 3 pounds
- Extension (e) = 0.6 feet
- Spring constant (K) =?
F = Ke
Divide both sides by e
K = F/ e
K = 3 / 0.6
K = 5 pound/foot
Thus, the spring constant of the spring is 5 pound/foot
<h3>How to determine the work done</h3>
- Spring constant (K) = 5 pound/foot
- Extention (e) = 0.7 feet
- Work done (Wd) =?
Wd = ½Ke²
Wd = ½ × 5 × 0.7²
Wd = 2.5 × 0.49
Wd = 1.23 foot-pound
Therefore, the work done in stretching the spring 0.7 feet is 1.23 foot-pound
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Answer:
Step-by-step explanation:
Let, 
Now, us simplify the given differential equation and write it in terms of D,
or, 
or, 
We have our auxiliary equation:
or, 
or, 
Therefore our solution is,
and, 
Applying the boundary conditions, we get,
Solving them gives us,
Hence,
