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Leno4ka [110]
3 years ago
13

A professor determined the relationship between the time spent studying (in hours) and performance on an exam.

Physics
1 answer:
lubasha [3.4K]3 years ago
3 0
Lets write again formula for determening Ann's performance.

P = 70.443 + 4,885*t

where t is in hours. This is equation with P(t) which means that P only depends on variable t. If we express t=2.6 in formula we will find her expected performance.

P = 83.144

Now, since it says that she scored 16 points less than expected we need to find value of P-16

P - 16 = 67.144

After round we get that the answer is 67
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A spherical aluminum ball of mass 1.26 kg contains an empty spherical cavity that is concentric with the ball. The ball barely f
V125BC [204]

The outer radius of the ball = 6.70cm.

<h3>What is Buoyant Force?</h3>

The upward force applied to an object that is fully or partially submerged in a fluid is known as the buoyant force.

Given: Mass of aluminum ball = m_{b}=1.26kg

To find: The outer radius of the ball.

Finding:

As Buoyant Force = F_{b}=e\times(g)\times\frac{4}{3}\pi(r)^{3},

The weight of the ball should be equal to the buoyant force since it floats on the water.

That is,

=> 1.26=e_{water}(g)(\frac{4}{3}\pi(r_{outer})^{3})

=> r_{outer}=(\frac{3\times1.26}{g\times(e_{water})4\times3.14})^\frac{1}{3}

Upon substitution of values of e_{water} and g, we get: r_{outer}=6.70cm

Hence, the outer radius of the ball = 6.70cm

To learn more about Buoyant Force, refer to the link: brainly.com/question/17009786

#SPJ4

4 0
2 years ago
A mixture of nitrogen and water vapor at 200oF, 1 atm has the molar analysis of 80% N2, 20% water vapor.a) If the mixture is coo
Illusion [34]

Answer:

p_g = 57.64 lb/in^2

Explanation:

Given data:

temperature of water vapor is 200 degree F

pressure is 1 atm

\from the standard water temperature tables , at temperature  200 degree F

p_{sat}  = 11.538 psia

\omega_1 = \frac{0.622 \times 0.2 \times 11.538}{14.7 - (0.2\times 11.538)}

\omega_1 = 0.115

at temp 200 degree F and\omega _1 = 0.115

\phi = 0.255

so relative humidity is given as

\phi = \frac{p_v}{p_g}

0.255 = \frac{14.7}{p_g}

p_g = 57.64 lb/in^2

6 0
4 years ago
The net electric flux through a cubic box with sides that are 22.0 cm long is 4950 N⋅m2/C . What charge is enclosed by the box?
Bond [772]

Answer:

43.83 nC

Explanation:

We know Q = ε₀Ψ where Q = charge enclosed by the cubic box,  ε₀ = permittivity of free space = 8.854 × 10⁻¹² F/m and Ψ = net electric flux through cubic box = 4950 Nm²/C

So, substituting the values of the variables into the equation, we have

Q = ε₀Ψ

= 8.854 × 10⁻¹² F/m × 4950 Nm²/C

= 43827.3 × 10⁻¹² C = 4.38273 × 10⁻⁸ C

= 43.8273 × 10⁻⁹ C

= 43.8273 nC

≅ 43.83 nC

5 0
3 years ago
GIVING 94 POINTS!!!!!! PLS HELP MEH
pishuonlain [190]

Answer:

A) asteroid

Explanation:

3 0
3 years ago
An important safety consideration with an electromagnet is to disconnect the wires when not in use because they can get ________
Rashid [163]

Answer:

Hot (A)

Explanation:

because there are electrons going through there, the friction between the metallic nuclei and electrons creates vibrations known as heat.

if you touch it the electrons will run through your body and caus damadge.

5 0
3 years ago
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