Answer:
Suppose that a couple invested $50,000 in an account when their child was born, to prepare for the child's college education. If the average interest rate is 4.4% compounded annually, ( A ) Give an exponential model for the situation, and ( B ) Will the money be doubled by the time the child turns 18 years old?
( A ) First picture signifies the growth of money per year.
( B ) Yes, the money will be doubled as it's maturity would be $108,537.29.
a = p(1 + \frac{r}{n} ) {}^{nt}a=p(1+
n
r
)
nt
a = 50.000.00(1 + \frac{0.044}{1} ) {}^{(1)(18)}a=50.000.00(1+
1
0.044
)
(1)(18)
a = 50.000.00(1 + 0.044) {}^{(1)(18)}a=50.000.00(1+0.044)
(1)(18)
a = 50.000.00(1.044) {}^{(18)}a=50.000.00(1.044)
(18)
50,000.00 ( 2.17074583287910578440507440 it did not round off as the exact decimal is needed.
a = 108.537.29a=108.537.29
Step-by-step explanation:
Hope This Help you!!
A)
Knights:
25n-C+1250=0
25n+1250=C
C=25n+1250
Legions:
30n+995-C=0
30n+995=C
C=30n+995
b)
fixed cost=b in y-intercept form
variable cost, dependent on n=m in y-intercept form
Knights:
fixed=1250
variable=25
Legions:
fixed=995
variable=30
c)
insert 45 into n for both formulas:
Knights:
25*45+1250=1125+1250=2375
Legions:
30*45+995=1350+995=2345
d)With 45 guests the Legion's Banquett Hall is cheaper, but due to the higher variable cost this changes with a few more people.
calculate break even point:
difference in variable cost=5 -> per person the cost difference will decrease by this much if another person joins
current price difference: 2375-2345=30
30/5=6 -> if there are 6 additional guest (total= 51) they will cost the same
if there are more than 6 additional guest (total >51) the knight's banquett will be cheaper.
Answer:
a = 13
Step-by-step explanation:
Hello!! This is how you do it!!
a - 7 = 3 (2)
a - 7 = 6
+ 7. +7
a = 13
Answer:
-1/16
Step-by-step explanation:
Put the values where the variables are and do the arithmetic.
1 to any power is 1, so you can ignore all of the 'a' factors. That leaves ...
1/(2b^3) = 1/(2(-2)^3) = 1/(2(-8)) = -1/16
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A calculator can help you figure this out.
