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blondinia [14]
3 years ago
15

A car company is doing crash tests and has installed forcesensors in the chairs and seatbelts to measure the forces thatare exer

ted on crash test dummies during a crash. In oneparticular test the sensors measure a horizontal net force onthe dummy of 39,400 N when the car comes to a complete stopfrom an initial speed of 35 m/s in 1.4 m. Treating the dummyas a point particle and assuming it comes to rest in the samedistance, what is the mass of the test dummy used during thistest
Physics
1 answer:
natulia [17]3 years ago
3 0

Answer:

m=90.1kg

Explanation:

From the question we are told that

Force F=39400

Initial speed V_1=35m/s

Distanced=1.4m

Generally the equation for acceleration is mathematically given by

a=\frac{V^2-U^2}{2d}

a=\frac{0^2-35^2}{21.4}

a=\frac{0^2-35^2}{21.4}

a=-437.5m/sec^2

Generally the equation for mass is mathematically given by

F=ma\\m=F/a

m=\frac{-39400}{-437.5}

m=90.1kg

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False is the correct answer.
6 0
4 years ago
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A 5.6 MeV (kinetic energy) proton enters a 0.39 T field, in a plane perpendicular to the field. What is the radius of its path?
Kisachek [45]

Answer:

the radius of the protons path is r = 0.85 m.

Explanation:

the force due to magnetic fields lead to the cetripetal force, such that:

F = q×v×B = m×(v^2)/r

         q×B = m×v/r

then:

r = m×v/q×B

r = p/q×B

then, the kinetic energy of the proton:

K = 1/2×m×v^2 = p^2/(2×m)

q×B = \sqrt{2×m×K}/r

    r =  \sqrt{2×m×K}/(q×B)

      =  \sqrt{2×(1.67×10^-27)×(5.3×1.60×10^-13)}/(1.60×10^-19×0.39)

      = 0.85 m  

7 0
4 years ago
Why are force fields used to describe magnetic force?
Illusion [34]

Answer:

If I'm not working I think the answer is C.

7 0
4 years ago
A positively charged particle travels horizontally northward and enters a region where a field may exist. This region may contai
nignag [31]

Answer:

Only magnetic field present

Explanation:

Since, the positively charged particle does not speed up or slow down, but it does deflect in the downward direction.  This means only magnetic field is present.

This is because electric field changes the velocity and magnetic field changes the direction.

The magnetic force F is given by

F = qvBsinθ

Where, q = charge magnitude, v = velocity of charge, B = strength of magnetic field. and θ =the angle between the directions of v and B.

4 0
3 years ago
S Two astronauts (Fig. P 11.55 ), each having a mass M , are connected by a rope of length d having negligible mass. They are is
jek_recluse [69]

The new rotational energy of the system(RE) = mv^{2}

How this is calculated?

  • Distance of each astronaut from centre of mass(m)=d/2

  • Moment of inertia of system

          I=m(\frac{d}{2} )^{2}+ m(\frac{d}{2} )^{2}\\   I =\frac{md^{2} }{2}

  • Speed of astronauts=v

  • So, angular speed,ω =  \frac{v}{d/2}

                                         =\frac{2v}{d}

  • Rotational energy of system= \frac{1}{2}  I \omega^{2}

                where, ω= angular speed

               RE=\frac{1}{2} *\frac{md^{2} }{2}*(\frac{2v}{d})^{2} \\RE     =mv^{2}

What is rotational energy?

  • Rotational energy or angular kinetic energy is kinetic energy due to the rotation of an object and is part of its total kinetic energy.
  • Looking at rotational energy separately around an object's axis of rotation, the following dependence on the object's moment of inertia is observed

To know more about rotational energy , refer:

brainly.com/question/13623190

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7 0
2 years ago
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