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Anastasy [175]
2 years ago
10

S Two astronauts (Fig. P 11.55 ), each having a mass M , are connected by a rope of length d having negligible mass. They are is

olated in space, orbiting their center of mass at speeds v . Treating the astronauts as particles, calculate (e) What is the new rotational energy of the system?
Physics
1 answer:
jek_recluse [69]2 years ago
7 0

The new rotational energy of the system(RE) = mv^{2}

How this is calculated?

  • Distance of each astronaut from centre of mass(m)=d/2

  • Moment of inertia of system

          I=m(\frac{d}{2} )^{2}+ m(\frac{d}{2} )^{2}\\   I =\frac{md^{2} }{2}

  • Speed of astronauts=v

  • So, angular speed,ω =  \frac{v}{d/2}

                                         =\frac{2v}{d}

  • Rotational energy of system= \frac{1}{2}  I \omega^{2}

                where, ω= angular speed

               RE=\frac{1}{2} *\frac{md^{2} }{2}*(\frac{2v}{d})^{2} \\RE     =mv^{2}

What is rotational energy?

  • Rotational energy or angular kinetic energy is kinetic energy due to the rotation of an object and is part of its total kinetic energy.
  • Looking at rotational energy separately around an object's axis of rotation, the following dependence on the object's moment of inertia is observed

To know more about rotational energy , refer:

brainly.com/question/13623190

#SPJ4

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