Polarized light waves are those that have only one plane of vibration. Polarization is the process by which non-polarized light is converted into polarised light. There are numerous ways to polarise light.
A characteristic of transverse waves called polarisation identifies the geometric angle of the oscillations. A transverse wave's oscillation direction is perpendicular to the wave's motion direction.
given
Only 72.0% of the light's intensity makes it through the sheet and hits another sheet of polarising material. The second sheet lets no light flow through it.
Given that no light passes through the second sheet because both sheets are crossed, the angle the transmission axis of the second sheet makes with the vertical is
θ₂ = θ₁ + 90°
= 31.94° + 90°
= 1 21.94°
for the first sheet and
Icos²θ₁ = I
I/I₀ = 0.72
θ₁ = cos⁻¹√(0.72)
= 31.94°
for the second sheet, respectively. This is because the malus law states that I = Iocos²θ₁ for the first sheet.
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Through emotion, facial expressions, body language, etc...
hope this helps
The <span>roles of products, reactants, and limiting reactant are significant in order for a chemical reaction to take place. The reactants are the components that are interacted in such a way that it would eventually produce a product, while on the other hand, a limiting reactant is used to regulate the products intended to produce.</span>
Before we go through the questions, we need to calculate and determine some values first.
r = 11.5 m
<span>m = 280 kg </span>
<span>Centripetal force = m x v^2/r = 280 x (17.1^2/11.5) = 7119.55 N
</span>
1) What is the magnitude of the normal force on the care when it is at the bottom of the circle.
<span>Centripetal force + mg = 7119.55 + (280 x 9.8) = 9863.55 N </span>
<span>2) What is the magnitude of the normal force on the car when it is at the side of the circle. </span>
<span>Centripetal force = 7119.55 N </span>
<span>3) What is the magnitude of the normal force on the car when it is at the top of the circle. </span>
<span>Centripetal force - mg = 7119.55 - (280 x 9.8) = 4375.55 N </span>
<span>4) What is the minimum speed of the car so that it stays in contact with the track at the top of the loop. </span>
√<span>(gr) </span>
√<span>(9.8 x 11.5) = 10.62 m/s</span>
I believe the answer is D. Thermal Conductivity
