Answer:
Explanation:
Be M1 and M2 the two massive objects and m the third one
The gravitational force over the third object at the beginning is zero (assuming that the position of the third object is x=0)
when the third object is displaced we have that the new position is x=Δx. Hence
I attached a scheme of the system
I hope this is useful for you
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The question is incomplete. The complete question is :
High-speed stroboscopic photographs show that the head of a 200 g golf club is traveling at 60 m/s just before it strikes a 50 g golf ball at rest on a tee. After the collision, the club head travels (in the same direction) at 40 m/s. Find the speed of the golf ball just after impact.
Solution :
We know that momentum = mass x velocity
The momentum of the golf club before impact = 0.200 x 60
= 12 kg m/s
The momentum of the ball before impact is zero. So the total momentum before he impact is 12 kg m/s. Therefore, due to the conservation of momentum of the two bodies after the impact is 12 kg m/s.
Now the momentum of the club after the impact is = 0.2 x 40
= 8 kg m/s
Therefore the momentum of the ball is = 12 - 8
= 4 kg m/s
We know momentum of the ball, p = mass x velocity
4 = 0.050 x velocity
∴ Velocity =
= 80 m/s
Hence the speed of the golf ball after the impact is 80 m/s.