All categories

3 years ago

What is the answer to 5x-7=13

Mathematics

2 answers:

liubo4ka [24]3 years ago

3 0

Answer:

x=4

Step-by-step explanation:

NemiM [27]3 years ago

3 0

Answer: x=4

Step-by-step explanation:

problem: 5x-7+13

step 1: add 7 to both sides

5x=20

step 2: divide both sides by 5

5x/5+20/5

step 3: simplify

x=4

You might be interested in

What's the product of 3 2/3 and 14 2/5

katen-ka-za [31]

$\frac{11}{3}$ × $\frac{72}{5}$
= $\frac{264}{5}$
= 52 4/5

7 0

3 years ago

Explain why all of these expressions have the same value. 4500÷90 450÷9 45÷0.9 4.5÷0.09

kramer

Answer:

The only thing that is changing in the equations is the placement of the decimal.

Step-by-step explanation:

8 0

3 years ago

5 3/4 times 1 3/4 and simplified

mrs_skeptik [129]

Answer:

I believe the answer will be 27/3

3 0

3 years ago

SOLUTION We observe that f '(x) = -1 / (1 + x2) and find the required series by integrating the power series for -1 / (1 + x2).

Ann [662]

Answer:

Required series is:

$\int{\frac{-1}{1+x^{2}} \, dx =-x+\frac{x^{3}}{3}-\frac{x^{5}}{5}+\frac{x^{7}}{7}+.....$

Step-by-step explanation:

Given that

$f'(x) = -\frac{1}{1 + x^{2}}$ ---(1)

We know that:

$\frac{d}{dx}(tan^{-1}x)=\frac{1}{1+x^{2}}$ ---(2)

Comparing (1) and (2)

$f'(x)=-(tan^{-1}x)$ ---- (3)

Using power series expansion for $tan^{-1}x$

$f'(x)=-tan^{-1}x=-\int {\frac{1}{1+x^{2}} \, dx$

$= -\int{ \sum\limits^{ \infty}_{n=0} (-1)^{n}x^{2n}} \, dx$

$= -\sum{ \int\limits^{ \infty}_{n=0} (-1)^{n}x^{2n}} \, dx$

$=-[c+\sum\limits^{ \infty}_{n=0} (-1)^{n}\frac{x^{2n+1}}{2n+1}]$

$=C+\sum\limits^{ \infty}_{n=0} (-1)^{n+1}\frac{x^{2n+1}}{2n+1}$

$=C-x+\frac{x^{3}}{3}-\frac{x^{5}}{5}+\frac{x^{7}}{7}+.....$

$tan^{-1}(0)=0 \implies C=0$

Hence,

$\int{\frac{-1}{1+x^{2}} \, dx =-x+\frac{x^{3}}{3}-\frac{x^{5}}{5}+\frac{x^{7}}{7}+.....$

7 0

4 years ago

Kdkvnsdfkfvqmehgrhgtevnm,vjwgqv

soldier1979 [14.2K]

Answer:

I don't know I can't understand do you know that you will lose 5 points

8 0

3 years ago