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Ainat [17]
3 years ago
12

The thermite reaction, in which powdered aluminum reacts with iron oxide, is highly exothermic: 2al(s) + fe2o3(s)→al2o3(s) + 2fe

(s) use standard enthalpies of formation to find δh∘rxn for the thermite reaction. express the heat of the reaction in kilojoules to four significant figures.
Chemistry
1 answer:
ycow [4]3 years ago
7 0
Answer is: <span>heat of the reaction is </span>-851,500 kJ.
Chemical reaction: 2Al + Fe₂O₃ → Al₂O₃ + 2Fe.
ΔHf(Fe₂O₃) = -824,2 kJ/mol; enthalpy of formation.
ΔHf(Al₂O₃) = -1675,7 kJ/mol.
By definition ΔH(element) = 0 kJ/mol.
ΔHrxn = ∑ΔH(products) - ∑ΔH(reactants).
ΔHrxn = 1 mol · (-1675,7 kJ/mol) - 1 mol · (-824,2 kJ/mol).
ΔHrxn = -851,500 kJ.

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Katarina [22]

The statement is true in this situation is C. The size of Ffric is the same as the size of Fapp:

From the diagram, since the body is in equilibrium, the sum of vertical forces equals zero. Also, the sum of horizontal forces equal zero.

So, ∑Fx = 0 and ∑Fy = 0

Since Fapp acts in the negative x - direction and Ffric acts in the positive x - direction,

∑Fx = -Fapp + Ffric = 0

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Fapp = Ffric

Also, since Fgrav acts in the negative y - direction and Fnorm acts in the positive y - direction,

∑Fy = Fnorm + (-Fgrav) = 0

Fnorm - Fgrav = 0

Fnorm = Fgrav

So, we see that the size of Fapp <u>equals</u> size of Ffric and the size of Fnorm <u>equals</u> the size of Fgrav.

So, the correct option is C

The statement which is true in this situation is C. The size of Ffric is the same as the size of Fapp.

Learn more about equilibrium of forces here:

brainly.com/question/12980489

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