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Ainat [17]
3 years ago
12

The thermite reaction, in which powdered aluminum reacts with iron oxide, is highly exothermic: 2al(s) + fe2o3(s)→al2o3(s) + 2fe

(s) use standard enthalpies of formation to find δh∘rxn for the thermite reaction. express the heat of the reaction in kilojoules to four significant figures.
Chemistry
1 answer:
ycow [4]3 years ago
7 0
Answer is: <span>heat of the reaction is </span>-851,500 kJ.
Chemical reaction: 2Al + Fe₂O₃ → Al₂O₃ + 2Fe.
ΔHf(Fe₂O₃) = -824,2 kJ/mol; enthalpy of formation.
ΔHf(Al₂O₃) = -1675,7 kJ/mol.
By definition ΔH(element) = 0 kJ/mol.
ΔHrxn = ∑ΔH(products) - ∑ΔH(reactants).
ΔHrxn = 1 mol · (-1675,7 kJ/mol) - 1 mol · (-824,2 kJ/mol).
ΔHrxn = -851,500 kJ.

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Maurinko [17]

Answer:

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Explanation:

From the given information:

O3* → O3                   (1)    fluorescence

O + O2                      (2)    decomposition

O3* + M → O3 + M    (3)     deactivation

The rate of fluorescence = rate of constant (k₁) × Concentration of reactant (cO)

The rate of decomposition is = k₂ × cO

The rate of deactivation = k₃ × cO × cM

where cM is the concentration of the inert molecule

The fraction (X) of ozone molecules undergoing deactivation in terms of the rate constants can be expressed by using the formula:

\text {X} =    \dfrac{ \text {rate of deactivation} }{ \text {(rate of fluorescence) +(rate of decomposition) + (rate of deactivation) }  } }

\text {X} =    \dfrac{  {k_3 \times cO \times cM} }{  {(k_1 \times cO) +(k_2 \times cO) + (k_3 \times cO \times cM) }  }

\text {X} =    \dfrac{  {k_3 \times cO \times cM} }{cO (k_1 +k_2 + k_3  \times cM) }

\text {X} =    \dfrac{  {k_3  \times cM} }{k_1 +k_2 + k_3  }    since  cM is the concentration of the inert molecule

7 0
3 years ago
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Answer:

elements in same group have same valence electron.

period of element is equal to valence shell

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if the elements are in a same group then they will be having same number of valence electron.

the period of an element in periodic table is equal to the valence shell of the element. that is if the valence electron are in 3 rd shell then the element will be in third period.

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Answer:

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8 0
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The formula we can use here is the Plancks equation:

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Therefore E is:

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