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Debora [2.8K]
2 years ago
10

Determine the molar mass of a gas that moves 1.25 times as fast as CO2.

Chemistry
1 answer:
Lerok [7]2 years ago
3 0

The molar mass of a gas that moves 1.25 times as fast as CO2 is 28.16 g.

<h3>Molar mass of the gas</h3>

The molar mass of the gas is determined by applying Graham's law of diffusion.

R₁√M₁ = R₂√M₂

R₁/R₂ = √M₂/√M₁

R₁/R₂ = √(M₂/M₁)

where;

  • R₁ is rate of the CO2 gas
  • M₁ is  molar mass of CO2 gas
  • R₂ is rate of the second gas
  • M₂ is the molar mass of the second gas

R₁/1.25R₁ = √(M₂/44)

1/1.25 =  √(M₂/44)

0.8 = √(M₂/44)

0.8² = M₂/44

M₂ = 0.8² x 44

M₂ = 28.16 g

Thus, the molar mass of a gas that moves 1.25 times as fast as CO2 is 28.16 g.

Learn more about molar mass here: brainly.com/question/21334167

#SPJ1

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Diatomic iodine [I2] decomposes at high temperature to form I atoms according to the reaction I2(g)⇌2I(g), Kc = 0.011 at 1200∘C
umka2103 [35]

Answer:

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Explanation:

For the equilibrium reaction,

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The expression for Kc for the reaction is:

K_c=\frac {\left[I_{Equilibrium} \right]^2}{\left[I_2_{Equilibrium} \right]}

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Applying in the above formula to find the equilibrium concentration of I as:

0.011=\frac {\left[I_{Equilibrium} \right]^2}{0.10}

So,

\left[I_{Equilibrium} \right]^2=0.011\times 0.10

\left[I_{Equilibrium} \right]^2=0.0011

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3 years ago
For below checmical equation (which may or may not be balanced), list the number of each type of atom on each side of the equati
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Answer:

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Right hand side:-

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Oxygen - 38

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Explanation:

The given reaction is:-

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Right hand side:-

Carbon - 12

Hydrogen - 28

Oxygen - 38

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5 0
3 years ago
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