Answer:
Volcanic eruptions is an example of a constructive force i believe.
Okay so i think to calculate volume change you use the ideal gas law . this is pressure x volume = amount of substance x ideal gas constant x temperature. i honestly don’t know where to go from there but i hope this helped a bit :(
There are 0.23 moles in 34.1g of AgCl, I believe.
Hope that helps
Hello!
* First Step: to know Avogrado's Law
We know that by the Law of Avogrado, for each mole of substance we have 6.02*10²³ atoms, if:
** Second Step: to know the molar mass of the solute
The molar mass of of magnesium = 24.30 g/mol
*** Third step: make the ratio mass / mol with atoms
1 mol we have 6.02*10²³ atoms
1 mole of Mg we have 24.30 g
Then we have:
24.30 g ------------- 6.02*10²³ atoms
x ----------------------- 6.98*10^24 atoms
![\dfrac{24.30}{x} = \dfrac{6.02*10^{23}}{6.98*10^{24}}](https://tex.z-dn.net/?f=%20%5Cdfrac%7B24.30%7D%7Bx%7D%20%3D%20%5Cdfrac%7B6.02%2A10%5E%7B23%7D%7D%7B6.98%2A10%5E%7B24%7D%7D%20%20)
multiply cross
![6.02*10^{23}*x = 24.30*6.98*10^{24}](https://tex.z-dn.net/?f=%206.02%2A10%5E%7B23%7D%2Ax%20%3D%2024.30%2A6.98%2A10%5E%7B24%7D%20)
![6.02*10^{23}\:x = 1.69614*10^{26}](https://tex.z-dn.net/?f=%206.02%2A10%5E%7B23%7D%5C%3Ax%20%3D%201.69614%2A10%5E%7B26%7D%20)
![x = \dfrac{1.69614*10^{26}}{6.02*10^{23}}](https://tex.z-dn.net/?f=%20x%20%3D%20%5Cdfrac%7B1.69614%2A10%5E%7B26%7D%7D%7B6.02%2A10%5E%7B23%7D%7D%20%20)
![\boxed{\boxed{x \approx 281.75\:grams}}\end{array}}\qquad\checkmark](https://tex.z-dn.net/?f=%20%5Cboxed%7B%5Cboxed%7Bx%20%5Capprox%20281.75%5C%3Agrams%7D%7D%5Cend%7Barray%7D%7D%5Cqquad%5Ccheckmark%20)
I Hope this helps, greetings ... DexteR! =)
Answer:
0.174 M
Explanation:
The same can be solve by using Nernst's equation
The Nernst's equation is:
![Ecell=E^{0}_{cell}-\frac{0.0592}{n}log\frac{[anodic]}{[cathodic]}](https://tex.z-dn.net/?f=Ecell%3DE%5E%7B0%7D_%7Bcell%7D-%5Cfrac%7B0.0592%7D%7Bn%7Dlog%5Cfrac%7B%5Banodic%5D%7D%7B%5Bcathodic%5D%7D)
For silver cell
n= 1
As both the compartments have silver nitrate solution,t the standard emf of cell will be zero.
Given
Ecell = 0.045
[Anodic compartment]= 1 M
Putting values
![0.045 = 0 -\frac{0.0592}{1}log(\frac{1}{x} )](https://tex.z-dn.net/?f=0.045%20%3D%200%20-%5Cfrac%7B0.0592%7D%7B1%7Dlog%28%5Cfrac%7B1%7D%7Bx%7D%20%29)
![0.760=log(\frac{1}{x})](https://tex.z-dn.net/?f=0.760%3Dlog%28%5Cfrac%7B1%7D%7Bx%7D%29)
Taking antilog and solving
[AgNO3]=0.174 M