Help me with this please.
1 answer:
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First multiply 3 and the 1
Then simplify b^2-4b+3=0
Then divide both numbers by 3 (b-3/3)(b-1/3)=0
If it doesn’t go in even like the second term then bring it before the B
Then equal both terms to 0 and solve
Then simplify b^2-4b+3=0
Then divide both numbers by 3 (b-3/3)(b-1/3)=0
If it doesn’t go in even like the second term then bring it before the B
Then equal both terms to 0 and solve
Answer:
301.44 mm
Step-by-step explanation:
Diameter of the inside ring of a packing tape = 80 mm
The tape surrounding the ring is 8 mm beyond the ring which means the diameter of the ring including the surrounding will be:
80 + 8 + 8 = 96 mm
and its radius will be = 96/2 = 48.
To find the distance around the outer edge of the tape, we need to calculate the circumference for the ring with the tape on it.
<em>Circumference = </em>
Circumference = 2 x 3.14 x 48 = 301.44 mm
Therefore, the distance around the outer edge of the tape is 301.44 mm.