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Crank
3 years ago
12

Please help!!!!! In a hurry

Mathematics
2 answers:
stepan [7]3 years ago
7 0

Answer:

1 /12. hope you get an a, thx

elena-s [515]3 years ago
4 0

Answer:

1/12

Step-by-step explanation:

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Which choice is a solution to the system of equations?
vodka [1.7K]

Answer:

B

Step-by-step explanation:

Given the 2 equations

y = 2x - 3 → (1)

y - 9 = - x → (2)

Substitute y = 2x - 3 into (2)

2x - 3 - 9 = - x

2x - 12 = - x ( add x to both sides )

3x - 12 = 0 ( add 12 to both sides )

3x = 12 ( divide both sides by 3 )

x = 4

Substitute x = 4 into either of the 2 equations and evaluate for y

Substituting into (1)

y = 2(4) - 3 = 8 - 3 = 5

Solution is (4, 5 ) → B

5 0
3 years ago
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Which table of values would you use to graph y = 3X^2?
horsena [70]

Answer:

y because its y i really dont no

7 0
3 years ago
I don’t get this please help me
8_murik_8 [283]
Answer: Brand B is

Explanation
(Brand A)24 diapers is 0.29¢ per diaper
(Brand B) 50 diapers is 0.27¢ per diaper
3 0
2 years ago
A set of 12 windup toys costs $9. What is the cost per windup toy?
-BARSIC- [3]

Answer:

0.75

Step-by-step explanation:

9 ÷ 12 = 0.75

hope this helps...

4 0
3 years ago
Read 2 more answers
Johnson Chemicals is considering two options for its supplier portfolio. Option 1 uses two local suppliers. Each has a "unique-e
sashaice [31]

Answer:

a) P=0.0175

b) P=0.0189

Step-by-step explanation:

For both options we have to take into account that not only the chance of a "superevent" will disable both suppliers.

The other situation that will disable both is that both suppliers have their "unique-event" at the same time.

As they are, by definition, two independent events, we can calculate the probability of having both events at the same time as the product of both individual probabilities.

a) Then, the probability that both suppliers will be disrupted using option 1 is

P_1=P_{se}+P_{ue}^2=0.015+(0.05)^2=0.015+0.0025=0.0175

b) The probability that both suppliers will be disrupted using option 2:

P_2=P_{se}+P_{ue}^2=0.002+(0.13)^2=0.002+0.0169=0.0189

Pue = probability of a unique event

Pse = probability of a superevent

3 0
3 years ago
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