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erma4kov [3.2K]

3 years ago

12

Graph the equation y=5/4x - 10 using the y intercept point and slope

1 answer:

tresset_1 [31]3 years ago

8 0

The graph is attached

in order to graph this equation, you need to start off by answering the question: where is the y-intercept?

y=mx+b

m= slope
b=y-intercept

according to y=5/4x-10, our y-intercept would be -10.

now we need to find the slope, represented by m, which is 5/4.

this is where rise over run comes in.

for this problem, we rise 5 units up and run 4 units towards the right.

we can repeat these as many times as it is necessary, and also do the negative counterpart to get the rest of the line.
(5 units down, 4 units left)

hope i helped!!

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The given line passes through the points and (-4, -3) and (4, 1).

Debora [2.8K]

Answer:

The equation of the line is y - 3 = -2(x + 4)

Step-by-step explanation:

* Lets explain how to solve the problem

- The slope of the line which passes through the points (x1 , y1) and

(x2 , y2) is $m=\frac{y_{2}-y_{1}}{x_{2}-x_{1}}$

- The product of the slopes of the perpendicular lines = -1

- That means if the slope of a line is m then the slope of the

perpendicular line to this line is -1/m

- The point-slope of the equation is $y - y_{1}=m(x - x_{1})$

* lets solve the problem

∵ A given line passes through points (-4 , -3) and (4 , 1)

∴ x1 = -4 , x2 = 4 and y1 = -3 , y2 = 1

∴ The slope of the line $m=\frac{1-(-3)}{4-(-4)}=\frac{1+3}{4+4}=\frac{4}{8}=\frac{1}{2}$

- The slope of the line perpendicular to this line is -1/m

∵ m = 1/2

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- Lets find the equation of the line whose slope is -2 and passes

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∵ x1 = -4 , y1 = 3

∵ m = -2

∵ y - y1 = m(x - x1)

∴ y - 3 = -2(x - (-4))

∴ y - 3 = -2(x + 4)

* The equation of the line is y - 3 = -2(x + 4)

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4 years ago