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Fiesta28 [93]
3 years ago
15

Matteo is adjusting a satellite because he finds it is not focusing the incoming radio waves perfectly. The shape of his satelli

te can be modeled by y^2=6x where x and y are modeled in inches. He realizes that the static is a result of the feed antenna shifting slightly off the focus point. What is the focus point of the satellite? (–1.5, 0) (0, –1.5) (0, 1.5) (1.5, 0)
Mathematics
2 answers:
OleMash [197]3 years ago
8 0

Answer:

Answer: (1.5, 0)

Step-by-step explanation:

natka813 [3]3 years ago
4 0

Answer: (1.5, 0)

Step-by-step explanation:

Given : The shape of his satellite can be modeled by y^2=6x where x and y are modeled in inches.

Now,the given equation y^2=6x is a equation of parabola.

Here, coefficient of x is positive, hence the parabola opens rightwards.

On comparing this equation with standard equation x^2=4mx, we get

4m=6\\\Rightarrow\ m=\frac{6}{4}=1.5

In standard equation, coordinates of focus=(m,0)

Thus for given equation coordinates of focus=(1.5,0)

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Answer:

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Step-by-step explanation:

pi's symbol is π, which will be used sometimes to make it easier later

The circumference is equal to diameter multiplied by pi. (Diameter is the length across the circle, radius the center of the circle to an edge point aka. half the diameter, and circumference is the edge length aka. perimeter of the circle.)

We can then remove the pi off the 10, as the diameter multiplied by pi is the circumference, so the diameter is 10.

Half of 10 is 5, the radius.

The formula for area of a circle is radius squared times pi, remember easily by π r ^2

We can plug in the radius into the formula to get

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Using the equation y = 3x – 5, what would the output be for an input of 4
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Read 2 more answers
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