1answer.
Ask question
Login Signup
Ask question
All categories
  • English
  • Mathematics
  • Social Studies
  • Business
  • History
  • Health
  • Geography
  • Biology
  • Physics
  • Chemistry
  • Computers and Technology
  • Arts
  • World Languages
  • Spanish
  • French
  • German
  • Advanced Placement (AP)
  • SAT
  • Medicine
  • Law
  • Engineering
Inga [223]
4 years ago
6

Which expression gives the distance between the points

Mathematics
1 answer:
Anna35 [415]4 years ago
6 0

Answer:

  D.  √((2 +4)² +(5 -8)²)

Step-by-step explanation:

The distance is found using the formula ...

  d = √((x1 -x2)² +(y1 -y2)²)

Selection D has this formula properly filled in with the values ...

  (x1, y1) = (2, 5)

  (x2, y2) = (-4, 8)

You might be interested in
How to find which cereal has the higher ratio of protein
Illusion [34]
It will be on the back or in the sides were it tell all the things its made out of etc
7 0
3 years ago
Find the local maximum and minimum values and saddle point(s) of the function. If you have three-dimensional graphing software,
vichka [17]

Answer:

A(-1,0) is a local maximum point.

B(-1,0)  is a saddle point

C(3,0)  is a saddle point

D(3,2) is a local minimum point.

Step-by-step explanation:

The given function is  

f(x,y)=x^3+y^3-3x^2-3y^2-9x

The first partial derivative with respect to x is  

f_x=3x^2-6x-9

The first partial derivative with respect to y is  

f_y=3y^2-6y

We now set each equation to zero to obtain the system of equations;

3x^2-6x-9=0

3y^2-6y=0

Solving the two equations simultaneously, gives;

x=-1,x=3  and y=0,y=2

The critical points are

A(-1,0), B(-1,2),C(3,0),and D(3,2).

Now, we need to calculate the discriminant,

D=f_{xx}(x,y)f_{yy}(x,y)-(f_{xy}(x,y))^2

But, we would have to calculate the second partial derivatives first.

f_{xx}=6x-6

f_{yy}=6y-6

f_{xy}=0

\Rightarrow D=(6x-6)(6y-6)-0^2

\Rightarrow D=(6x-6)(6y-6)

At A(-1,0),

D=(6(-1)-6)(6(0)-6)=72\:>\:0 and f_{xx}=6(-1)-6=-18\:

Hence A(-1,0) is a local maximum point.

See graph

At B(-1,2);

D=(6(-1)-6)(6(2)-6)=-72\:

Hence, B(-1,0) is neither a local maximum or a local minimum point.

This is a saddle point.

At C(3,0)

D=(6(3)-6)(6(0)-6)=-72\:

Hence, C(3,0) is neither a local minimum or maximum point. It is a saddle point.

At D(3,2),

D=(6(3)-6)(6(2)-6)=72\:>\:0 and f_{xx}=6(3)-6=12\:>\:0

Hence D(3,2) is a local minimum point.

See graph in attachment.

3 0
3 years ago
... the product of the width and the height...
irga5000 [103]

Step-by-step explanation:

The product of <em>a</em> and <em>b</em> is equal to <em>a · b.</em>

Let <em>w - width</em> and <em>l - length</em>, then the product of the width and the lenght is

<em>w · h = wh</em>

7 0
3 years ago
Suppose a simple random sample of size nequals81 is obtained from a population with mu equals 79 and sigma equals 18. ​(a) Descr
Daniel [21]

Answer:

(a) The sampling distribution of\overline{X} = Population mean = 79

(b)  P ( \overline{X} greater than 81.2 ) =  0.1357

(c) P (\overline{X} less than or equals 74.4 ) = .0107

(d) P (77.6 less than \overline{X} less than 83.2 ) = .7401

Step-by-step explanation:

Given -

Sample size ( n ) = 81

Population mean (\nu) = 79

Standard deviation (\sigma ) = 18

​(a) Describe the sampling distribution of \overline{X}

For large sample using central limit theorem

the sampling distribution of\overline{X} = Population mean = 79

​(b) What is Upper P ( \overline{X} greater than 81.2 )​ =

P(\overline{X}> 81.2)  = P(\frac{\overline{X} - \nu }{\frac{\sigma }{\sqrt{n}}}> \frac{81.2 - 79}{\frac{18}{\sqrt{81}}})

                    =  P(Z> 1.1)

                    = 1 - P(Z<   1.1)

                    = 1 - .8643 =

                    = 0.1357

(c) What is Upper P (\overline{X} less than or equals 74.4 ) =

P(\overline{X}\leq  74.4) = P(\frac{\overline{X} - \nu }{\frac{\sigma }{\sqrt{n}}}\leq  \frac{74.4- 79}{\frac{18}{\sqrt{81}}})

                    = P(Z\leq  -2.3)

                    = .0107

​(d) What is Upper P (77.6 less than \overline{X} less than 83.2 ) =

P(77.6< \overline{X}<   83.2) = P(\frac{77.6- 79}{\frac{18}{\sqrt{81}}})< P(\frac{\overline{X} - \nu }{\frac{\sigma }{\sqrt{n}}}\leq  \frac{83.2- 79}{\frac{18}{\sqrt{81}}})

                                = P(- 0.7< Z<   2.1)

                                 = (Z<   2.1) - (Z<   -0.7)

                                  = 0.9821 - .2420

                                   = 0.7401

3 0
3 years ago
(free upvote) write an algebraic expression for the following phrase:
sashaice [31]
4 - (x + 6)
or -x -2
.......
3 0
4 years ago
Other questions:
  • PLEASE HELP ME FOR EXTRA POINTS AND BRAINLIEST ANWSER
    9·2 answers
  • Mr. william phisics class lasts 7/8 of an hour, 3/10 is used on arming up . How many minutes do they take to warm up..NOT FRACTI
    15·1 answer
  • Is 45/27 equivalent??????
    15·1 answer
  • Which number is a factor of 15?<br><br> 6<br> 8<br> 5<br> 45
    14·2 answers
  • Which equation represents the data shown in the table below?
    12·1 answer
  • EXTRA POINTS PLEAS HELP ME !!!!!!!!!!!! :3 ◑ω◐ 14 points if you can help ◑ω◐
    8·2 answers
  • Please help with question attached on picture.
    5·1 answer
  • The function y= -0.2 + 0.5 represents the percent y (in decimal form) of battery power remaining x hours after you turn on a lap
    11·2 answers
  • ...................................
    13·1 answer
  • Find the slope and y-intercept of each linear equation 30 points
    13·1 answer
Add answer
Login
Not registered? Fast signup
Signup
Login Signup
Ask question!