Answer:

General Formulas and Concepts:
<u>Pre-Algebra</u>
Order of Operations: BPEMDAS
- Brackets
- Parenthesis
- Exponents
- Multiplication
- Division
- Addition
- Subtraction
<u>Algebra I</u>
<u>Algebra II</u>
- Distance Formula:

Step-by-step explanation:
<u>Step 1: Define</u>
Point (-5, 6) → x₁ = -5, y₁ = 6
Point (3, 2) → x₂ = 3, y₂ = 2
<u>Step 2: Find distance </u><em><u>d</u></em>
Simply plug in the 2 coordinates into the distance formula to find distance <em>d</em>
- Substitute in points [Distance Formulas]:

- [Distance] [√Radical] (Parenthesis) Add/Subtract:

- [Distance] [√Radical] Evaluate exponents:

- [Distance] [√Radical] Add:

- [Distance] [√Radical] Simplify:

Answer:
The answer would be A and B
Step-by-step explanation:
I really did not have an explanation because I found out by guessing because I did not understand. :)
Answer:

Step-by-step explanation:
Have in mind the definition of the term
, and now work on what the term
is based on the previous definition:

In the next step do NOT combine the numerical values, but try to identify the
term (
) in the expression (notice the use of square brackets to group the relevant terms):
![a_{n+1}=4\,n+4-1\\a_{n+1}=[4\,n-1]+4\\a_{n+1}=a_n+4](https://tex.z-dn.net/?f=a_%7Bn%2B1%7D%3D4%5C%2Cn%2B4-1%5C%5Ca_%7Bn%2B1%7D%3D%5B4%5C%2Cn-1%5D%2B4%5C%5Ca_%7Bn%2B1%7D%3Da_n%2B4)
So now we have the term "
" defined in a recursive manner based on the previous term "
"
Answer:
I am pretty sure it is 56 because all you have to do is dvided and it comes out to 56.25 but you cant have .25 because that is not an equal peice so yeah I think it is 56