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2 years ago

Question is on picture

Mathematics

2 answers:

adoni [48]2 years ago

8 0

Answer:

4 or 4/1 (both the same thing just with plotting point writing 4/1 is easier for me so I know to go up 4 over 1 :) )

Step-by-step explanation:

Parallel lines have the same slope, so both lines will have the same slope. Use line 1’s points to find the slope with the formula

(y1-y2)/(x1-x2)

(5-1)/(-2-(-3)

4/1=4

tamaranim1 [39]2 years ago

6 0

Answer:

Answer is 4 .

Step-by-step explanation:

As parallel lines have same slopes..

Therefore,cordinate y1-y2 /x1-x2=Slope of L2

5-1/(-2-(-3))

=4/1

=4 ,Slope of line l2

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Round to the nearest hundreth

n200080 [17]

Answer:

∠ B ≈ 66.42°

Step-by-step explanation:

Using the cosine ratio in the right triangle

cos B = $\frac{adjacent}{hypotenuse}$ = $\frac{BC}{AB}$ = $\frac{2}{5}$ , thus

B = $cos^{-1}$ ( $\frac{2}{5}$ ) ≈ 66.42° ( to the nearest hundredth )

3 0

3 years ago

A 75-gallon tank is filled with brine (water nearly saturated with salt; used as a preservative) holding 11 pounds of salt in so

Debora [2.8K]

Let $A(t)$ = amount of salt (in pounds) in the tank at time $t$ (in minutes). Then $A(0) = 11$ .

Salt flows in at a rate

$\left(0.6\dfrac{\rm lb}{\rm gal}\right) \left(3\dfrac{\rm gal}{\rm min}\right) = \dfrac95 \dfrac{\rm lb}{\rm min}$

and flows out at a rate

$\left(\dfrac{A(t)\,\rm lb}{75\,\rm gal + \left(3\frac{\rm gal}{\rm min} - 3.25\frac{\rm gal}{\rm min}\right)t}\right) \left(3.25\dfrac{\rm gal}{\rm min}\right) = \dfrac{13A(t)}{300-t} \dfrac{\rm lb}{\rm min}$

where 4 quarts = 1 gallon so 13 quarts = 3.25 gallon.

Then the net rate of salt flow is given by the differential equation

$\dfrac{dA}{dt} = \dfrac95 - \dfrac{13A}{300-t}$

which I'll solve with the integrating factor method.

$\dfrac{dA}{dt} + \dfrac{13}{300-t} A = \dfrac95$

$-\dfrac1{(300-t)^{13}} \dfrac{dA}{dt} - \dfrac{13}{(300-t)^{14}} A = -\dfrac9{5(300-t)^{13}}$

$\dfrac d{dt} \left(-\dfrac1{(300-t)^{13}} A\right) = -\dfrac9{5(300-t)^{13}}$

Integrate both sides. By the fundamental theorem of calculus,

$\displaystyle -\dfrac1{(300-t)^{13}} A = -\dfrac1{(300-t)^{13}} A\bigg|_{t=0} - \frac95 \int_0^t \frac{du}{(300-u)^{13}}$

$\displaystyle -\dfrac1{(300-t)^{13}} A = -\dfrac{11}{300^{13}} - \frac95 \times \dfrac1{12} \left(\frac1{(300-t)^{12}} - \frac1{300^{12}}\right)$

$\displaystyle -\dfrac1{(300-t)^{13}} A = \dfrac{34}{300^{13}} - \frac3{20}\frac1{(300-t)^{12}}$

$\displaystyle A = \frac3{20} (300-t) - \dfrac{34}{300^{13}}(300-t)^{13}$

$\displaystyle A = 45 \left(1 - \frac t{300}\right) - 34 \left(1 - \frac t{300}\right)^{13}$

After 1 hour = 60 minutes, the tank will contain

$A(60) = 45 \left(1 - \dfrac {60}{300}\right) - 34 \left(1 - \dfrac {60}{300}\right)^{13} = 45\left(\dfrac45\right) - 34 \left(\dfrac45\right)^{13} \approx 34.131$

pounds of salt.

7 0

1 year ago

Please help me if you can

Luda [366]

A) 100 degrees (congruent angle)
B) 45 degrees (congruent angle)
C) 90 degrees (right angle)
D) 99 degrees (congruent angle)
E) 30 degrees (congruent angle)
F) 30 degrees (180-150=30, that is to find the other angle that is congruent to f)

5 0

2 years ago

What is the value of x?

deff fn [24]

The value of x is the variable of the number it is closer to

8 0

3 years ago

Write (3p^3)^2 without exponents

rodikova [14]

Answer:

3p*3p*3p*3p*3p*3p

Step-by-step explanation:

Multiply exponents

3p^6

expand

3p*3p*3p*3p*3p*3p = 3p^6

4 0

2 years ago