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mel-nik [20]
3 years ago
11

What is the most convenient method to solve the quadratic equation ( x + 4 )² = 15

Mathematics
2 answers:
Mademuasel [1]3 years ago
8 0

Answer:

B

Step-by-step explanation:

IgorC [24]3 years ago
7 0

Answer:

Factoring

Step-by-step explanation:

(x+4)² = 15

x² + 8x + 16 = 15

x² + 8x + 1 = 0

x =  \frac{ - 8 +  \sqrt{64 - 4} }{2}  =  - 4 +  \sqrt{15}  \\  \\ x =  \frac{ - 8 -  \sqrt{64 - 4} }{2}  =  - 4 -  \sqrt{15}

I hope this helps you :)

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Answer:

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Step-by-step explanation:

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3 years ago
Factor completely 2x3 + x2 - 18x - 9
melisa1 [442]
Factor the following:
2 x^3 + x^2 - 18 x - 9

Factor terms by grouping. 2 x^3 + x^2 - 18 x - 9 = (2 x^3 + x^2) + (-18 x - 9) = x^2 (2 x + 1) - 9 (2 x + 1):
x^2 (2 x + 1) - 9 (2 x + 1)

Factor 2 x + 1 from x^2 (2 x + 1) - 9 (2 x + 1):
(2 x + 1) (x^2 - 9)

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Factor the difference of two squares. x^2 - 3^2 = (x - 3) (x + 3):

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7 0
3 years ago
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The length of a rectangle is increasing at a rate of 6 cm/s and its width is increasing at a rate of 5 cm/s. When
atroni [7]

Answer:

The area of the rectangle is increasing at a rate of 84 square centimeters per second.

Step-by-step explanation:

The area for a rectangle is given by the formula:

A=w\ell

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We are given that the length of the rectangle is increasing at a rate of 6 cm/s and that the width is increasing at a rate of 5 cm/s. In other words, dl/dt = 6 and dw/dt = 5.

First, differentiate the equation with respect to <em>t</em>, where <em>w</em> and <em>l</em> are both functions of <em>t: </em>

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By the Product Rule:

\displaystyle \frac{dA}{dt}=\frac{dw}{dt}\ell +\frac{d\ell}{dt}w

Since we know that dl/dt = 6 and that dw/dt = 5:

\displaystyle \frac{dA}{dt}=5\ell + 6w

We want to find the rate at which the area is increasing when the length is 12 cm and the width is 4 cm. Substitute:

\displaystyle \frac{dA}{dt}=5(12)+6(4)=84\text{ cm}^2\text{/s}

The area of the rectangle is increasing at a rate of 84 square centimeters per second.

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3 years ago
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slamgirl [31]

Answer:

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Step-by-step explanation:

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