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2 years ago

Three friends are travelling by aeroplane and want to pay as little as possible in total for their luggage.

Mathematics

1 answer:

In-s [12.5K]2 years ago

4 0

Answer:

B.25$

Step-by-step explanation:

to make the money less one of the freinds will carry 9kg and the other 12 kg the last one carries the left luggage weighing 7kg and 6kg which add up to 13kg.

the first freind won't pay anything as he is passing 9kg luggage

the second will pay : 12-10 =2 so 2kg*5$=10$

the last freind will pay 13-10=3 so 3kg*5$=15$

to find the total money the pay we will add 10$ and 15$ which became 25$.

hope this helped.

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Someone help me with this please

anzhelika [568]

for question 1

Area of Base B =45×25 = 1125 cm²

perimeter of base P = 2(45+25) = 140 cm

Height = 15 cm

Using the formula

Surface area = 2B + Ph

A = 2×1125 + 140×15= 4350 cm²

Voume = Bh = 1125×15= 16875 cm³

For question 2,

Area of base = 7× 5/2= 17.5 cm²

Perimeter of base = (7+7+7) = 21 cm

Surface area = 2B + Ph

Surface area of prism = 2×17.5+ 21×10 = 245cm²

Volume = Bh = 17.5×10 = 175 cm³

6 0

3 years ago

Read 2 more answers

HELP PLZ RN<3 which graph displays a rate of change of 2.5?

Ilya [14]

Answer:

The second graph.

Step-by-step explanation:

The first graph has a negative slope, so that can't be the right answer.

The last graph isn't steep enough to show a rate of 2.5.

This leaves us with the middle graph which is correct.

3 0

3 years ago

1. The scale of a map is 1:1000. What are the actual dimensions of a

kakasveta [241]

Answer:

Step-by-step explanation:

4 cm × 1000 = 4000 cm = 40 meters

3 cm × 1000 = 3000 cm = 30 meters

A 4 cm by 3 cm section on the map represents 40 m by 30 m.

area = 40 m × 30 m = 1200 m²

6 0

3 years ago

Solve 5x^2 - 7x+2 -0 by completing the square. What are the solutions?

trapecia [35]

5x² - 7x + 2 = 0

5(x² - 7/5 x) + 2 = 0

5(x² - 7/5 x + 49/100 - 49/100) + 2 = 0

5(x² - 2 • 7/10 x + (7/10)²) - 49/20 + 2 = 0

5(x - 7/10)² - 9/20 = 0

5(x - 7/10)² = 9/20

(x - 7/10)² = 9/100

x - 7/10 = ± √(9/100)

x - 7/10 = ± 3/10

x = 7/10 ± 3/10

x = 10/10 = 1 or x = 4/10 = 2/5

6 0

3 years ago

A researcher wishes to estimate the average blood alcohol concentration (BAC) for drivers involved in fatal accidents who are f

Mnenie [13.5K]

Answer:

A 90% confidence interval for the mean BAC in fatal crashes in which the driver had a positive BAC is [0.143, 0.177] .

Step-by-step explanation:

We are given that a researcher randomly selects records from 60 such drivers in 2009 and determines the sample mean BAC to be 0.16 g/dL with a standard deviation of 0.080 g/dL.

Firstly, the pivotal quantity for finding the confidence interval for the population mean is given by;

P.Q. = $\frac{\bar X-\mu}{\frac{s}{\sqrt{n} } }$ ~ $t_n_-_1$

where, $\bar X$ = sample mean BAC = 0.16 g/dL

s = sample standard deviation = 0.080 g/dL

n = sample of drivers = 60

$\mu$ = population mean BAC in fatal crashes

Here for constructing a 90% confidence interval we have used a One-sample t-test statistics because we don't know about population standard deviation.

So, a 90% confidence interval for the population mean, $\mu$ is;

P(-1.672 < $t_5_9$ < 1.672) = 0.90 {As the critical value of t at 59 degrees of

freedom are -1.672 & 1.672 with P = 5%} P(-1.672 < $\frac{\bar X-\mu}{\frac{s}{\sqrt{n} } }$ < 1.672) = 0.90

P( $-1.672 \times {\frac{s}{\sqrt{n} } }$ < ${\bar X-\mu}$ < $1.672 \times {\frac{s}{\sqrt{n} } }$ ) = 0.90

P( $\bar X-1.672 \times {\frac{s}{\sqrt{n} } }$ < $\mu$ < $\bar X+1.672 \times {\frac{s}{\sqrt{n} } }$ ) = 0.90

90% confidence interval for $\mu$ = [ $\bar X-1.672 \times {\frac{s}{\sqrt{n} } }$ , $\bar X+1.672 \times {\frac{s}{\sqrt{n} } }$ ]

= [ $0.16-1.672 \times {\frac{0.08}{\sqrt{60} } }$ , $0.16+1.672 \times {\frac{0.08}{\sqrt{60} } }$ ]

= [0.143, 0.177]

Therefore, a 90% confidence interval for the mean BAC in fatal crashes in which the driver had a positive BAC is [0.143, 0.177] .

7 0

3 years ago