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Snezhnost [94]
2 years ago
5

Two similar rectangles are shown. Which statement is true? A) The area of rectangle B is 1 3 the area of rectangle A. B) The are

a of rectangle B is 1 9 the area of rectangle A. C) The area of rectangle B is nine times the area of rectangle A. Eliminate D) The area of rectangle B is three times the area of rectangle A
Mathematics
1 answer:
kenny6666 [7]2 years ago
6 0

Answer:

I think it is 19 I not really sure

Step-by-step explanation:

o work it out of my paper and I got 19

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Can someone please answer these questions
Leona [35]

Answer:

15 . Undefined

16. undefined

Step-by-step explanation:

3 0
2 years ago
What is the answer to this
Sever21 [200]
I think it’s d I’m not sure though
8 0
2 years ago
-114=-5x-2(4x+18)<br> ????????
SVETLANKA909090 [29]

Primeiro multiplica o -2 com tudo que tem dentro do parenteses (chuveirinho)  -114 = -5x -2(4x+18)

-2 . 4x = -8x        +     -2 . 18 = -36        =   -8x-36


Agora soma os números com incógnitas (no caso x)

-114 = - 5x - 8x -36    


Joga a incógnita do outro, tornando positiva

-114 = -13x - 36            

13x -114 = -36


e o 114 do outro lado, ficando positiva também  

13x -114 = -36

13x  = - 36 + 114

13x = 78

x = 78 /13

x= 6


ESPERO TER AJUDADO :)


8 0
3 years ago
A right triangle has a leg b of length 7 and a hypotenuse of length 11 what is the length of the other leg a?
scoray [572]

Answer: 8.5


Step-by-step explanation:


5 0
2 years ago
Write -3+4i in the form r(cosx+isinx)
Zanzabum
-3+4i is a complex number that satisfies

\begin{cases}r\cos x=-3\\[1ex]r\sin x=4\\[1ex]r=\sqrt{(-3)^2+4^2}\end{cases}

The last equation immediately tells you that r=5.

So you have

\begin{cases}\cos x=-\dfrac35\\[1ex]\sin x=\dfrac45\end{cases}

Dividing the second equation by the first, you end up with

\dfrac{\sin x}{\cos x}=\tan x=\dfrac{\dfrac45}{-\dfrac35}=-\dfrac43

Because the argument's cosine is negative and its sine is positive, you know that \dfrac\pi2. This is important to know because it's only the case that y=\tan x\implies \arctan y=x whenever -\dfrac\pi2. The inverse doesn't exist otherwise.

However, you can restrict the domain of the tangent function so that an inverse can be defined. By shifting the argument of tangent by \pi, we have

\tan(x-\pi)=y\implies x=\pi+\arctan y

All this to say

\tan x=-\dfrac43\implies x=\pi+\arctan\left(-\dfrac43\right)\approx2.2143\text{ rad}\approx126.9^\circ

So, -3+4i=5(\cos126.9^\circ+i\sin126.9^\circ).
5 0
3 years ago
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