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2 years ago

1. Determine whether line KM and line ST are Parallel, Pers

Mathematics

1 answer:

Andrews [41]2 years ago

7 0

Answer:

Since the slope of KM and ST are different, they are not parallel

Step-by-step explanation:

Slope of line KM = $\frac{5}{8}$

Slope of ST = $-\frac{8}{5}$

Determine whether the lines are perpendicular;

Solution:

We can use the slope of a line to determine whether they are perpendicular or parallel to one another.

Parallel lines do not meet one another

Perpendicular lines cross one another at an angle of 90°

Two lines are parallel if their slopes are the same;

Since the slope of KM and ST are different, they are not parallel

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243 - 167 =76
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2 years ago

The specifications for manufacturing a steel rod stipulate that the length must be 8.225 ± 0.125 inches. The Minimum allowable l

zmey [24]

Answer:

Minimum - 8.1 inches

Maximum - 8.35 inches

Step-by-step explanation:

The specifications for manufacturing a steel rod stipulate that the length must be 8.225 ± 0.125 inches.

This means that the minimum length must not be 0.125 inches less than 8.225 inches and the maximum length must not be 0.125 inches greater than 8.225 inches.

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2 years ago

Whats the proper abbreviation for twenty-five micrograms

scoundrel [369]

Answer:

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3 years ago

What's the flux of the vector field F(x,y,z) = (e^-y) i - (y) j + (x sinz) k across σ with outward orientation where σ is the po

emmasim [6.3K]

$\displaystyle\iint_\sigma\mathbf F\cdot\mathrm dS$
$\displaystyle\iint_\sigma\mathbf F\cdot\mathbf n\,\mathrm dS$
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Since you want to find flux in the outward direction, you need to make sure that the normal vector points that way. You have

$\mathbf r_u=\dfrac\partial{\partial u}[2\cos v\,\mathbf i+\sin v\,\mathbf j+u\,\mathbf k]=\mathbf k$
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The cross product is

$\mathbf r_u\times\mathbf r_v=\begin{vmatrix}\mathbf i&\mathbf j&\mathbf k\\0&0&1\\-2\sin v&\cos v&0\end{vmatrix}=-\cos v\,\mathbf i-2\sin v\,\mathbf j$

So, the flux is given by

$\displaystyle\iint_\sigma(e^{-\sin v}\,\mathbf i-\sin v\,\mathbf j+2\cos v\sin u\,\mathbf k)\cdot(\cos v\,\mathbf i+2\sin v\,\mathbf j)\,\mathrm dA$
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$\displaystyle-5\int_0^{2\pi}e^{-\sin v}\cos v\,\mathrm dv+10\int_0^{2\pi}\sin^2v\,\mathrm dv$
$\displaystyle5\int_0^0e^t\,\mathrm dt+5\int_0^{2\pi}(1-\cos2v)\,\mathrm dv$

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$\displaystyle5\int_0^{2\pi}(1-\cos2v)\,\mathrm dv=5\left(v-\dfrac12\sin2v\right)\bigg|_{v=0}^{v=2\pi}=10\pi$

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3 years ago

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Grace [21]

Answer:

Step-by-step explanation:

7 0

2 years ago