R + b = 146. Supposing that b=r+28,
r + (r+28) = 146, or 2r + 28 = 146.
Simplifying: 2r = 118. Then r = 59, and b = r+28 = 59+28 = 87 blue marbles
9514 1404 393
Answer:
- 0 < x < 4
- (- ∞ < x < 0) ∪ (4 < x < ∞)
- x ∈ {0, 4}
Step-by-step explanation:
1. The solution is the set of x-values for which the graph is above the x-axis, where y = 0. Those x-values are in the interval (0, 4).
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2. The solution is the set of x-values for which the graph is below the x-axis. Those x-values are in either of the two intervals (-∞, 0) or (4, ∞).
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3. The x-intercepts of the graph are x=0 or x=4.
Y= 3/4x - 2 (-2,10)= (x1,y1)
The slope is -4/3 of the perpendicular line:
Then:
y-y1=m(x-x1)
y-10=(-4/3)(x+2)
y=-(4/3)x -8/3 +10
y= -(4/3)x +22/3 (That's the answer)
Y + 5 = 0
y >= -5
Therefore, you would choose the first answer.
No it isn’t. it works for the first equation but not the second
