How many numbers from 1 to 100 can be divided by 2 with none leftover.

Convert 0.34285714285 into an improper fraction

Stolb23 [73]

Answer:

34285714285/100000000000

Step-by-step explanation:

To write 0.34285714285 as a fraction you have to write 0.34285714285 as the numerator and put 1 as the denominator. Now you multiply the numerator and denominator by a number that makes the numerator to a whole number.

And finally, we have:

0.34285714285 as a fraction equals 34285714285/100000000000

5 0

3 years ago

A university dean is interested in determining the proportion of students who receive some sort of financial aid. Rather than ex

Olenka [21]

Answer:

a

The 90% confidence interval that estimate the true proportion of students who receive financial aid is

$0.533 < p < 0.64$

b

$n = 1789$

Step-by-step explanation:

Considering question a

From the question we are told that

The sample size is n = 200

The number of student that receives financial aid is $k = 118$

Generally the sample proportion is

$\^ p = \frac{k}{n}$

=> $\^ p = \frac{118}{200}$

=> $\^ p = 0.59$

From the question we are told the confidence level is 90% , hence the level of significance is

$\alpha = (100 - 90 ) \%$

=> $\alpha = 0.10$

Generally from the normal distribution table the critical value of $\frac{\alpha }{2}$ is

$Z_{\frac{\alpha }{2} } = 1.645$

Generally the margin of error is mathematically represented as

$E = Z_{\frac{\alpha }{2} } * \sqrt{\frac{\^ p (1- \^ p)}{n} }$

=> $E = 1.645 * \sqrt{\frac{0.59 (1- 0.59)}{200} }$

=> $E = 0.057$

Generally 90% confidence interval is mathematically represented as

$\^ p -E < p < \^ p +E$

=> $0.533 < p < 0.64$

Considering question b

From the question we are told that

The margin of error is E = 0.03

From the question we are told the confidence level is 99% , hence the level of significance is

$\alpha = (100 - 99 ) \%$

=> $\alpha = 0.01$

Generally from the normal distribution table the critical value of is

$Z_{\frac{\alpha }{2} } = 2.58$

Generally the sample size is mathematically represented as

$[\frac{Z_{\frac{\alpha }{2} }}{E} ]^2 * \^ p (1 - \^ p )$

=> $n = [\frac{2.58}{0.03} ]^2 * 0.59 (1 - 0.59 )$

=> $n = 1789$

8 0

3 years ago

I am confused about how to do this problem and I don't think it should be hard, but I just don't know how to approach it, so if

solniwko [45]

Answer:

a) (0.555, 0) and (6, 0)

b) r = -3 and r = 1.8

c) (0.875, 0.676)

d) (0, 1.235)

Step-by-step explanation:

Set each term in the numerator and denominator equal to 0 and find r.

In the numerator:

r = 7/8, 5/9, or 6

In the denominator:

r = 9/5, 7/8, or -3

Zeros in the numerator that aren't in the denominator are r-intercepts.

Zeros in the denominator that aren't in the numerator are vertical asymptotes.

Zeros in both the numerator and the denominator are holes.

a) (0.555, 0) and (6, 0)

b) r = -3 and r = 1.8

c) Evaluate m(r) at r = 7/8. To do that, first divide out the common term (-8r + 7) from the numerator and denominator.

m(r) = (-9r+5)² (r−6)² / ( (-5r+9)² (r+3)² )

m(⅞) = (-9×⅞+5)² (⅞−6)² / ( (-5×⅞+9)² (⅞+3)² )

m(⅞) = (-23/8)² (-41/8)² / ( (37/8)² (31/8)² )

m(⅞) = (-23)² (-41)² / ( (37)² (31)² )

m(⅞) = 0.676

The hole is at (0.875, 0.676).

d) Evaluate m(r) at r = 0.

m(0) = (-9×0+5)² (0−6)² / ( (-5×0+9)² (0+3)² )

m(0) = (5)² (-6)² / ( (9)² (3)² )

m(0) = 1.235

The m(r)-intercept is (0, 1.235).

5 0

3 years ago

Find the zeros of the function y = x^2-1.

kumpel [21]

Answer:

Step-by-step explanation:

x^2-1=0

Add 1 to both sides of the equation.

x^2= 1

Take the square root of both sides of the equation to eliminate the exponent on the left side.

x = ± √ 1

Any root of 1 is x = ± 1

First, use the positive value of the ±

to find the first solution.

x= 1

Next, use the negative value of the ±

to find the second solution.

x = − 1

The complete solution is the result of both the positive and negative portions of the solution.

x = 1 , − 1

4 0

2 years ago

Read 2 more answers

Which of the following points lies on the graph of the function y= 2.3*?

Rainbow [258]

If the equation is $y = 2\cdot 3^x$ (2 times 3^x)

Then the answer is d. (0,2)

This is because plugging x = 0 leads to y = 2 as shown below

$y = 2\cdot 3^x\\\\y = 2\cdot 3^0\\\\y = 2\cdot 1\\\\y = 2$

3 0

3 years ago