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zubka84 [21]
2 years ago
8

Phosphorus has three electrons in its 3p sublevel and sulfur has four. Phosphorus should have the lower ionization energy but it

does not, sulfur does. Why? A. Phosphorus has 2 of its electrons paired in the 3p sublevel, which makes them harder to remove, or "ionize." B. Sulfur has 2 of its electrons paired in the 3p sublevel. The mutual repulsion of their negative charges makes them easier to remove, or "ionize." C. Because sulfur has more electrons, they are further from the nucleus and thus easier to remove and form an ion. D. Since sulfur has more electrons, it has more chances to form an ion.
Chemistry
1 answer:
Nadya [2.5K]2 years ago
8 0

Answer:

B

Explanation:

First of all it is important to know that a half filled orbital is particularly stable. In phosphorus all the electrons occur singly in the 3p sublevel minimizing inter electronic repulsion hence it is more difficult to remove an electron from this energetically stable arrangement. In sulphur, electrons are paired in one of the 3p orbitals thereby lowering the energy of that level due to instability caused by interelectronic repulsion between two electrons in the same orbital.

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The mass of the copper cylinder is 177065.856g

Given:

Radius of the copper cylinder R=12cm

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To find:

Mass of the copper cylinder

<u>Step by Step by explanation:</u>

Solution:

According to the formula, Mass can be calculated as

\rho=\frac{m}{v} and from this

m=\rho \times v

Where, m=mass of the cylinder

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v=volume of the cylinder

And also cylinder is provided with radius and height value.

So volume of the cylinder is calculated as

v=\pi r^{2} h

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h=height of the cylinder=44cm

Thus, v=3.14 \times 12^{2} \times 44

v=3.14 \times 144 \times 44

v=19895.04 \mathrm{cm}^{3}

And we know that, m=\rho \times v

Substitute the known values in the above equation we get

m=8.90 \times 19895.04  

m=177065.856g or 177.065kg

Result:

Thus the mass of the copper cylinder is 177065.856g

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3 years ago
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