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kramer
4 years ago
15

Density of a liquid if 500.cm3 weighs 752.0 g​

Chemistry
1 answer:
aksik [14]4 years ago
5 0

Explanation:

jrjrji8 que se ha dicho nada. pero si lo que se le puede dar un paseo de la ciudad, y el 5 que se le puede pasar por alto

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A burner on a stove produces?
loris [4]

Answer:

thermal energy

Explanation:

7 0
3 years ago
Potassium iodide (ki) exhibits predominantly ionic bonding. the k and i ions have electron structures that are identical to whic
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Inert gases are also called noble gases. They are the elements found in Group 8A in the periodic table. They are inert because they don't react with other elements. This is because they have the most stable electronic configuration. That's why elements form ions to gain or give way electrons so that they conform with the electronic configuration of the nearest inert gas. Basing on the periodic table, the nearest inert gas to K is Argon. The nearest inert gas to I is Xenon.
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3 years ago
Identify the molecule with the highest boiling point. NH3 CO2 C2H2 C3H8
Black_prince [1.1K]

Answer:

NH3

Explanation:

NH3 molecules make strong intermolecular H bondings and also because of the increase in the size of atomic radius.

4 0
4 years ago
If the pH is 3.94 what is the concentration of H
solong [7]

Answer:

If pOH is 3.05, pH is 10.95 or

[H+]=1.122⋅10−11 mol/L

Explanation:

pH=−log(H+)Now, what is H+

if your pH is 10.95 (since pH+pOH=14, your pH=10.95).

(H+)=10 −10.95

(H+)=1.122⋅10 −11

This is your hydrogen ion concentration: [H+]=0.00000000001122  mol/L

7 0
3 years ago
How many mL of 0.100 M NaCl would be required to make a 0.0365 M solution of NaCl when diluted to 150.0 mL with water?
Tatiana [17]

Answer:

54.75 mL

Explanation:

First calculate the number of moles of NaCl in the 150mL solution of NaCl

0.0365 moles should be present on 1000cm3 or 1dm3 of water.

1L = 1 dm3

1 mL = 1 / 1000 dm3

150 mL = 150/1000 dm3 = 0.15 dm3

If x moles are present in 0.15 dm3,

x/ 0.15 = 0.0365

We get x= 0.0365 × 0.15 mol

Now x amount of moles should be taken from the initial 0.100 M NaCl solution

So 0.1 moldm-3 = 0.0365× 0.15 mol / V

we get V = 0.05475 dm3

V= 0.05475 L

V= 54.75 mL

3 0
3 years ago
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