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3 years ago

13

What is the sum of 6/12 and 1/2

2 answers:

Degger [83]3 years ago

4 0

Answer:

1/2

Step-by-step explanation:6/12 is 1/2 of the fraction meaning that 6/12 is = to 1/2.

Sphinxa [80]3 years ago

4 0

Answer:

12 / 12

Step-by-step explanation:

LCM of 12 and 2 = 12

1 / 2

= ( 1 / 2 ) x ( 6 / 6 )

= ( 1 x 6 ) / ( 2 x 6 )

= 6 / 12

6 / 12 + 1 / 2

= 6 / 12 + 6 / 12

= ( 6 + 6 ) / 12

= 12 / 12

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3 years ago

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Step-by-step explanation:

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2 years ago

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Two vertical angles will always equal 180 degrees

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3 years ago

Callie has a new kitten. They can weigh 3 pounds less than half the weight of Callie‘s cat. Together the cat and kitten weigh 18

gavmur [86]

Answer:

The weight of cat is <u>14 pounds</u> and the weight of kitten is <u>4 pounds</u>.

Step-by-step explanation:

Given:

Callie has a new kitten. It can weigh 3 pounds less than half the weight of Callie‘s cat. Together the cat and kitten weigh 18 pounds.

Now, to find the weight of each animal:

Let the cat's weight be $x.$

And the kitten weight = $\frac{x}{2} -3$

Total weight of cat and kitten = 18 pounds.

Now, to set an equation to get the weight of each animal:

$(x)+(\frac{x}{2}-3)=18$

$x+\frac{x}{2} -3=18$

$\frac{2x+x-6}{2} =18$

$\frac{3x-6}{2} =18$

<em>Multiplying both sides by 2 we get:</em>

<em /> $3x-6=36$ <em />

<em>Adding both sides by 6 we get:</em>

<em /> $3x=42$ <em />

<em>Dividing both sides by 3 we get:</em>

<em /> $x=14\ pounds.$ <em />

<em>The weight of cat = 14 pounds.</em>

Substituting the value of $x$ to get the kitten's weight:

$\frac{x}{2} -3\\\\=\frac{14}{2}-3\\\\=7-3\\\\=4.$

<em>The kitten's weight = 4 pounds.</em>

Therefore, the weight of cat is 14 pounds and the weight of kitten is 4 pounds.

7 0

3 years ago

Which choice is equivalent to the product below when x>0?

V125BC [204]

Answer:

D

Step-by-step explanation:

Using the rule of radicals

$\sqrt{\frac{a}{b} }$ = $\frac{\sqrt{a} }{\sqrt{b} }$

$\sqrt{a\\}$ × $\sqrt{b}$ ⇔ $\sqrt{ab}$

Given

$\sqrt{\frac{6}{x} }$ × $\sqrt{\frac{x^2}{24} }$

= $\frac{\sqrt{6} }{\sqrt{x} }$ × $\frac{x^2}{24}$

= $\frac{\sqrt{6} }{\sqrt{x} }$ × $\frac{x}{2 \sqrt{6\\} }$

Cancel $\sqrt{6}$ on numerator/ denominator

= $\frac{1}{\sqrt{x} }$ × $\frac{x}{2\\}$

= $\frac{1}{\sqrt{x} }$ × $\frac{(\sqrt{x})^2 }{2}$

Cancel $\sqrt{x}$ on numerator/ denominator, leaving

= $\frac{\sqrt{x} }{2}$ → D

4 0

3 years ago