Answer:
Explanation:
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In this case, according to the given information, it turns out possible for us to solve for the molarity of the KOH solution by knowing this base react in a 1:1 mole ratio with nitric acid, HNO3; thus, we can write the following equation, as their moles are the same at the endpoint:
Which in terms of molarities and volumes is:
Thus, we solve for the molarity of the base (KOH) to obtain:
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Answer:
Before we get into the first law of thermodynamics we need to understand the relation between heat and work and the concept of internal energy. Just like mass, energy is always conserved i.e. it can neither be created nor destroyed but it can be transformed from one form to another. Internal energy is a thermodynamic property of the system that refers to the energy associated with the molecules of the system which includes kinetic energy and potential energy.
Whenever a system goes through any change due to interaction of heat, work and internal energy, it is followed by numerous energy transfer and conversions. However, during these transfers, there is no net change in the total energy.
Similarly, if we look at the first law of thermodynamics it affirms that heat is a form of energy. What it means is that the thermodynamic processes are governed by the principle of conservation of energy. The first law of thermodynamics is also sometimes referred to as the Law of Conservation of Energy
Explanation:
Answer:
Ba²⁺(aq) + 2 Cl⁻(aq) + 2 NH₄⁺(aq) + SO₄²⁻(aq) ⇒ 2 NH₄⁺(aq) + 2 Cl⁻(aq) + BaSO₄(s)
Explanation:
Let's consider the molecular equation that occurs when aqueous BaCl₂ and aqueous (NH₄)₂SO₄ are mixed in solution to form aqueous NH₄Cl and solid BaSO₄. This is a double displacement reaction.
BaCl₂(aq) + (NH₄)₂SO₄(aq) ⇒ 2 NH₄Cl(aq) + BaSO₄(s)
The complete ionic equation includes all the ions and insoluble species.
Ba²⁺(aq) + 2 Cl⁻(aq) + 2 NH₄⁺(aq) + SO₄²⁻(aq) ⇒ 2 NH₄⁺(aq) + 2 Cl⁻(aq) + BaSO₄(s)
The chemical reaction would be written as:
2Na + Cl2 = 2NaCl
Since we are given the amounts of the reactants available for reaction, we have to determine the limiting reactant. And use this amount to calculate for the theoretical yield.
55 g Na ( 1 mol / 22.99 g ) = 2.39 mol Na
67.2 f Cl2 ( 1 mol / 70.9 g ) = 0.95 mol Cl2
Therefore, the limiting reactant would be Cl2 since it is the one consumed completely.
0.95 Cl2 ( 1 mol NaCl / 1 mol Cl2) = 0.95 NaCl produced from the reaction
