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Katen [24]
2 years ago
14

No attempt was made to test sodium with hydrochloric acid. Why not?

Chemistry
1 answer:
Fiesta28 [93]2 years ago
3 0

Answer:

the reaction is violent and quick

Explanation:

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Organic chemistry is the study of compounds containing
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It's carbon. All organic compounds contain carbon
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Electrons and protons (attract/repel) each other
tensa zangetsu [6.8K]
Electrons are (-) and Protons are (+) 
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A 6.00 L container of N_2 has a temperature of 273 K. Calculate the volume if the temperature is doubled.
vfiekz [6]
V1/T1 =V2/T2 (using charles law)

V1=6.00
V2=?
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Making V2 the subject of formula the equation then becomes

V2= V1xT2/T1

6.00x263/273=6.0L
4 0
2 years ago
Which of the following statements is true?
hammer [34]

Lord dragon you are wrong.

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8 0
3 years ago
Read 2 more answers
when a solution of sodium chloride is added to a solution of copper(ii) nitrate, no precipitate is observed. Write the molexular
zhuklara [117]

Explanation:

1.

Cu(NO3)2 + 2NaCl(aq) --> CuCl2(aq) + 2NaNO3(aq)

2.

Cu(NO3)2 + 2NaOH(aq) --> Cu(OH)2(s) + 2NaNO3(aq)

A light blue precipitate of Cu(OH)2 is formed and NaNO3 in solution.

3.

Cu(NO3)2(aq) --> Cu2+(aq) + 2NO3^-2(aq)

2NaOH(aq) --> 2Na+(aq) + 2OH-(aq)

Cu2+(aq) + 2OH-(aq) --> Cu(OH)2(aq)

2Na+(aq) + 2NO3^-2(aq) --> 2NaNO3(aq)

4.

The reaction in both Questions 1 and 2 is called Double displacement reaction. A double-replacement reaction exchanges the cations and/or or the anions of two ionic compounds. A precipitation reaction is a double-replacement reaction in which one product is a solid precipitate (precipitated) while the other in solution.

Since the cation and anions in Qustion 1 were exchanged, the same was done for Question 2, hence the identity of the precipitate in Question 2 was got.

6 0
3 years ago
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