Question

a gas at 155 kPa and 25 degrees C occupies a container with an initial volume of 1.00 L. By changing the volume, the pressure of the gas increases to 605 kPa as the temperature is raised to 125 degrees C. What is the new volume?

Answer 1

First thing, you convert from kPa to Pa. Then, you find the atm value of the Pa you got.

155 kPa = 155 000 Pa
1 atm = 101 325 Pa
x atm = 155 000 Pa
You divide 101 325 over 155 000 and you get about 1.53
So, 155 000 Pa = 1.53 atm.
So, T (temperature) = 25 + 273 = 298

605 kPa = 605 000 Pa
1 atm = 101 325 Pa
x atm = 605 000 Pa
You divide 605 000 over 101 325 and you get about 5.97 
So 605 000 Pa = 5.97 atm
So, T = 125 + 273 = 398

P1 * V1/T1 = P2 * V2/T2
1.53 * 1/298 = 5.97 * V2/398
You calculate ad you get V2 = 0.342 L

Hope this Helps :)

Answer 2

Answer:

First thing, you convert from kPa to Pa. Then, you find the atm value of the Pa you got.

155 kPa = 155 000 Pa

1 atm = 101 325 Pa

x atm = 155 000 Pa

You divide 101 325 over 155 000 and you get about 1.53

So, 155 000 Pa = 1.53 atm.

So, T (temperature) = 25 + 273 = 298

605 kPa = 605 000 Pa

1 atm = 101 325 Pa

x atm = 605 000 Pa

You divide 605 000 over 101 325 and you get about 5.97

So 605 000 Pa = 5.97 atm

So, T = 125 + 273 = 398

P1 * V1/T1 = P2 * V2/T2

1.53 * 1/298 = 5.97 * V2/398

You calculate ad you get V2 = 0.342 L

Hope this Helps :)

Explanation: