Answer:
12.5%
Explanation:
Initial percentage of carbon 14 = 100%
Final percentage = ?
Time passed = 17.1 * 1000 years = 17100 years
Half life of carbon 14 = 5,730 years.
So how many Half lives are in 17100 years?
Number of Half lives = Time passed / Half life = 3.18 ≈ 3
First Half life;
100% --> 50%
Second Half life;
50% --> 25%
Third Half life ;
25% --> 12.5%
Answer
147.06N
Explanation:
MA=Load/Effort
6.8=1000/x
Finding x you make x the subject and divide 1000 by 6.8 which is 147.06N
Answer:
5-chloro-2-methylcyclohexanol
Explanation:
There is no structure for the compound, but we can analyze the proposed options using the IUPAC rules to name organic compounds.
IUPAC rules state that to name an organic compound, first we have to identify the priorities for the functional groups present in the compound. <em><u>In this case, the priority functional group is the alcohol group</u></em>, <u><em>so we will start the counting of the carbons in this group.</em></u> Then, the counting of carbon atoms is followed by the next substituents so they have the lowest possible numbers, <em><u>in this case, we can assign the number 2 to the methyl group and 5 to the chloride group</u></em>, and name the compound in alphabetical order, using commas to separate the words from the numbers and with no space between the words.
Since the other options involve: <u>high countings for the susbtituents groups (</u><u>3</u><u>-chloro-</u><u>6</u><u>-methylcyclohexanol)</u>, <u>wrong assignation of priority functional group (</u><u>1-chloro</u><u>-4-methylcyclohexanol), wrong sequence of counting in the compound (</u><u>2-methyl-3-chloro</u><u>cyclohexanol) and no alphabetical order to name the compound (2-</u><u>methyl</u><u>-5-</u><u>chloro</u><u>cyclohexanol), </u><u>the correct option is:</u>
5-chloro-2-methylcyclohexanol
Have a nice day!
Yeah what is the question
Answer:
Option (C) 4.5 liters
Explanation:
1mole of a gas occupy 22.4L at stp.
This implies that 1mole of He also occupy 22.4L at stp.
From the question given, we were asked to find the volume occupied by 0.20 mole of He at STP. This can be achieved by doing the following:
1mole of He occupied 22.4L.
Therefore, 0.2mol of He will occupy = 0.2 x 22.4L = 4.48 = 4.5L