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3 years ago

Pushing a rock from a hill top is called

Physics

1 answer:

wariber [46]3 years ago

6 0

It's called "utter disregard for the safety and welfare
of the people standing at the bottom of the hill".

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PLEASE HELPPPP MEEE!!!!!!!!!!!!!!!

ozzi

The answer is choice C.

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3 years ago

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If an egg person starts from rest then falls directly downward and hits the ground with a velocity of 12 m/s but

Anni [7]

Answer:

Explanation: Determine the gravitational acceleration. ...

Decide whether the object has an initial velocity. ...

Choose how long the object is falling. ...

Calculate the final free fall speed (just before hitting the ground) with the formula v = v₀ + gt

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2 years ago

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What is a personified statement?

slamgirl [31]

Answer:

A statement about you

Explanation:

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3 years ago

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A mass of 2 kg is attached to a spring and placed on a horizontal surface. The spring has a spring constant of 20 N/m, and the s

Sergio [31]

The speed of the mass : <em><u>v = 0.316 m/s</u></em>

<h3>Further explanation</h3>

The energy used to press a spring is included as the potential energy

Can be formulated:

$\displaystyle E_p=\frac{1}{2}kx^2$

Ep= potential energy

k = spring constant

x = change in spring length

If the spring is released from its pressure, this potential energy will turn into kinetic energy

so applies the law of conservation of mechanical energy (Em)

Ek = Ep

A mass of 2 kg is attached to a spring, a spring constant of 20 N/m, and the spring is compressed 0.1 m past its natural length.

m = 2 kg

k = 20 N/m

x = 0.1 m

$\displaystyle Ep=Ek\\\\\frac{1}{2}kx^2=\frac{1}{2}mv^2\\\\kx^2=mv^2\\\\20\times0.1^2=2\times v^2\\\\v^2=0.1\\\\v=\sqrt{0.1}\\\\v=0.316~m/s$

<h3>Learn more</h3>

Hooke's law

brainly.com/question/2648431

Keywords : spring,mass, spring constant,compressed position

5 0

3 years ago

A nichrome wire and an aluminum wire, each with the same initial resistance, have the same change in resistance when heated sepa

Svetach [21]

Answer:

The ratio of temperature change of nichrome wire to the temperature change of aluminum wire is found to be <u>9.75</u>

Explanation:

The change in resistances and initial resistances of the wires are:

Change in Resistance of Nichrome Wire = ΔR₁

Change in Resistance of Aluminum Wire = ΔR₂

Initial Resistance of Nichrome Wire = R₁

Initial Resistance of Aluminum Wire = R₂

Also, it is given that the change in resistance and initial resistance of both wires is equal. Therefore,

ΔR₁ = ΔR₂ ---------- eqn (1)

R₁ = R₂ ---------- eqn (2)

The change in Resistance due to temperature is given by formula:

ΔR = R α ΔT

Therefore, eqn (1) becomes:

R₁ α₁ ΔT₁ = R₂ α₂ ΔT₂

using eqn (2):

α₁ ΔT₁ = α₂ ΔT₂

ΔT₁/ΔT₂ = α₂/α₁

where,

α₁ = Temperature coefficient of resistance of nichrome = 0.4 x 10⁻³ °C⁻¹

α₂ = Temperature coefficient of resistance of aluminum = 3.9 x 10⁻³ °C⁻¹

Therefore,

ΔT₁/ΔT₂ = (3.9 x 10⁻³ °C⁻¹)/(0.4 x 10⁻³ °C⁻¹)

6 0

4 years ago