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Readme [11.4K]
3 years ago
13

Alice builds another model to describe the movement of the particles of a substance after it changes state due to thermal energy

being added or removed. which of the below claim safely be made using her model​
Physics
1 answer:
sweet-ann [11.9K]3 years ago
4 0

Explanation:

so sorry

don't know but please mark me as brainliest please

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Your friend says that inertia is a force that keeps things in their place, either at rest or in motion. Do you and your discussi
Galina-37 [17]

Answer:

yes i agree

Explanation:

because law of inertia state that object remain at rest or in motion unless external force apply on it

8 0
3 years ago
A diver jumps off a cliff 50m high and needs to clear the rock that extend outward 5.0m from the base of the cliff. The diver ju
igor_vitrenko [27]

Answer:

He should run at least at 1.5 m/s

The diver will enter the water at an angle of 87° below the horizontal.

Explanation:

Hi there!

The position and velocity of the diver are given by the following vectors:

r = (x0 + v0x · t, y0 + v0y · t + 1/2 · g · t²)

v = (v0x, v0y + g · t)

Where:

r = position vector at time t

x0 = initial horizontal position

v0x = initial horizontal velocity

t = time

y0 = initial vertical position

v0y = initial vertical velocity

g = acceleration due to gravity (-9.8 m/s² considering the  upward direction as positive)

v = velocity vector at time t

Please, see the attached figure for a description of the problem. Notice that the origin of the frame of reference is located at the jumping point so that x0 and y0 = 0.

We know that, to clear the rocks, the position vector r final (see figure) should be:

r final = ( > 5.0 m, -50 m)

So let´s find first at which time the y-component of the vector r final is - 50 m:

y = y0 + v0y · t + 1/2 · g · t²

-50 m = 2.1 m/s · t - 1/2 · 9.8 m/s² · t²

0 = -4.9 m/s² · t² + 2.1 m/s · t + 50 m

Solving the quadratic equation

t = 3.4 s

Now, we can calculate the initial horizontal velocity using the equation of the x-component of the position vector knowing that at t =3.4 the horizontal component should be greater than 5.0 m:

x = x0 + v0x · t      (x0 = 0)

5.0 m < v0x · 3.4 s

v0x > 5.0 m / 3.4 s

v0x > 1.5 m/s

The initial horizontal velocity should be greater than 1.5 m/s

To find the angle at which the diver enters the water, we have to find the magnitude of the final velocity (vector vf in the figure). We already know the magnitude of the x-component of the vector vf, since the horizontal velocity is constant. So:

vfx > 1.5 m/s

Now, let´s calculate vfy:

vfy = v0y + g · t

vfy = 2.1 m/s - 9.8 m/s² · 3.4 s

vfy = -31 m/s

Let´s calculate the minimum magnitude that the final velocity will have if the diver safely clears the rocks. Let´s consider the smallest value allowed for vfx: 1.5 m/s. Then:

|v| = \sqrt{(1.5 m/s)^{2} + (31m/s)^{2}} = 31 m/s

Then the final velocity of the diver will be greater or equal than 31 m/s.

To find the angle, we have to use trigonometry. Notice in the figure that the vectors vf, vfx and vy form a right triangle in which vf is the hypotenuse, vfx is the adjacent side and vfy is the opposite side to the angle. Then:

cos θ = adjacent / hypotenuse = vfx / vf = 1.5 m/s / 31 m/s

θ = 87°

The diver will enter the water at an angle of 87° below the horizontal.

8 0
3 years ago
Considering , will F ever equal zero?
Kamila [148]
No it will not because F will equal 3 not 0

4 0
3 years ago
Read 2 more answers
Can someone help me
Nady [450]
The answer is D 10x21
7 0
3 years ago
Calculate the magnitude of the force, in newtons, exerted by a boxing glove on an opponent’s face, if the glove and face togethe
saul85 [17]

Answer:

5437.5 N

Explanation:

from the question we are given the following:

mass = 7.25 kg

initial speed (u) = 10.5 \frac{m}{s}

finial velocity (v) = 0

compression (s) = -7.35 cm = -0.0735 m (the negative sign is because the face is compressed, so there is a decrease)

we know that force = mass x acceleration,  

we have our mass but need to find the acceleration. we can get the acceleration by applying the formula below

v^{2} = u^{2} + 2as

therefore

0 = 10.5^{2} + (-2)× a × 0.0735[/tex]

a = \frac{10.5^{2} }{ 2 × 0.0735}[/tex]

a = 750

from F = m x a

force = 7.25 x 750 = 5437.5 N

7 0
3 years ago
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