The process that produces the energy radiated by stars is nuclear fusion in the core.
For a star on the main sequence, it's the fusion of hydrogen nuclei into helium.
<span>In Ionic type of bonding, electrons are lost (more
protons than electrons and positive charge) or gained (more electrons than
protons, still a negative charge) by atoms, and the atoms are held together by
electrical attraction in the process. Covalent bondings are the sharing of electrons
as well as partial bondings. Covalent bondings’ electrons have the same charges
thus, there is no gaining or losing electrons in the process of sharing. Strong
bondings are applicable only to Hydrogen (H) atoms. </span>
Answer:
a) The current density ,J = 2.05×10^-5
b) The drift velocity Vd= 1.51×10^-15
Explanation:
The equation for the current density and drift velocity is given by:
J = i/A = (ne)×Vd
Where i= current
A = Are
Vd = drift velocity
e = charge ,q= 1.602 ×10^-19C
n = volume
Given: i = 5.8×10^-10A
Raduis,r = 3mm= 3.0×10^-3m
n = 8.49×10^28m^3
a) Current density, J =( 5.8×10^-10)/[3.142(3.0×10^-3)^2]
J = (5.8×10^-10) /(2.83×10^-5)
J = 2.05 ×10^-5
b) Drift velocity, Vd = J/ (ne)
Vd = (2.05×10^-5)/ (8.49×10^28)(1.602×10^-19)
Vd = (2.05×10^-5)/(1.36 ×10^10)
Vd = 1.51× 10^-5
Answer:
A) 
B) 
C) 
D) mosquitoes speed in part B is very much larger than that of part C.
Explanation:
Given:
- Distance form the sound source,
- sound intensity level at the given location,
- diameter of the eardrum membrane in humans,
- We have the minimum detectable intensity to the human ears,
(A)
<u>Now the intensity of the sound at the given location is related mathematically as:</u>
..........................................(1)
<em>As we know :</em>
is the energy transferred to the eardrums per second.
(B)
mass of mosquito, 
<u>Now the velocity of mosquito for the same kinetic energy:</u>
(C)
Given:
- Sound intensity,
<u>Using eq. (1)</u>
Now, power:
Hence:
(D)
mosquitoes speed in part B is very much larger than that of part C.
