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BigorU [14]
2 years ago
13

Compare the signs of ƒ for lenses and mirrors.

Physics
2 answers:
ELEN [110]2 years ago
4 0

Answer:

A positive focal point for concave mirrors and convex lenses.

A negative focal point for convex mirrors and concave lenses.

Explanation:

STALIN [3.7K]2 years ago
3 0

Answer:

simple

Explanation:

<h3>CONCAVE MIRRORS AND LENSES</h3>

<h3>f= negative</h3>

<h3>CONVEX MIRRORS AND LENSES</h3><h3 /><h3>f= positive</h3>

<h3>PLEASE FOLLOW ME AND MARK IT BRAINLIEST</h3>

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An air-filled pipe is found to have successive harmonics at 945 Hz , 1215 Hz , and 1485 Hz . It is unknown whether harmonics bel
Aleonysh [2.5K]

Answer:

L = 0.635m

Explanation:

This problem involves the concept of stationary waves in pipes. For pipes closed at one end,

The frequency f = nv/4L for n = 1,3,5....n

For pipes open at both ends

f = nv/2L for n = 1,2,3,4...n

Assuming the pipe is closed at one end and that velocity of sound is 343m/s in air. If we are right we will obtain a whole number for n.

The film solution can be found in the attachment below.

8 0
3 years ago
Joe runs 10 m north, 20 m south, 9m south, and then 15 m north. What is Joe's<br> displacement?
tresset_1 [31]

Answer:

Joes displacement is 54m

4 0
1 year ago
Which of the following is a part of the digestive system
BlackZzzverrR [31]

The Pancreas

<em>Is an inflammation organ that lies in the lower part of the stomach which plays a big part in the digestive system.</em>

3 0
2 years ago
If potential energy at point A is 12 joules, what is the potential energy at D?
Irina-Kira [14]

Answer:

In D: 3J

Explanation:

Potential energy: Ep=mgh where m is the mass, h altitude.

In point A: h=20cm=0.2m

Epa=12=0.2×mg. Thus mg=12/0.2=60N

For point D: hd=5cm=0.05m

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5 0
3 years ago
An object in free fall is at heights y1, y2, and y3 at times t1, t2, and t3 respectively.
Dvinal [7]

Answer:

  a = (v₃₂ - v₂₁) / (t₃₂ -t₂₁)

Explanation:

This is an exercise of average speed, which is defined with the variation of the distance in the unit of time

         v = (y₃ - y₂) / (t₃-t₂)

the midpoint of a magnitude is the sum of the magnitude between 2

         t_mid = (t₂ + t₃) / 2

the same reasoning is used for the mean acceleration

         a = (v_f - v₀) / (t_f - t₀)

   

in our case

        a = (v₃₂ - v₂₁) / (t₃₂ -t₂₁)

5 0
2 years ago
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